[RESOLVED] openfiledialog question

' Display an OpenFileDialog so the user can select a Cursor.
Dim openFileDialog1 As New OpenFileDialog()

openFileDialog1.Filter = "VMware Configuration files (*.txt)|*.txt|All files (*.*)|*.*"
openFileDialog1.Title = "Selecteer een bestand"

' Show the Dialog.
' If the user clicked OK in the dialog and
' a .XML file was selected, open it.

If openFileDialog1.ShowDialog() = Windows.Forms.DialogResult.OK Then


I gote a problem whit this code
you can open a txt file but when
I click an the button cancel he gives error
Ik know that with this it to do has


If openFileDialog1.ShowDialog() = Windows.Forms.DialogResult.OK Then
I can just open it but i wanne cancel to how do i do that

There shouldn't be an error really. At least not from what you have shown. I guess there's code that tries to execute outside of the Open file dialog but it's hard to say without seeing it. You could try this:

vb Code:

If OFD.ShowDialog = Windows.Forms.DialogResult.OK Then
 
      'You have code here
 
ElseIf OFD.ShowDialog = Windows.Forms.DialogResult.Cancel Then
 
       Exit Sub  'Don't execute any code that follows this
 
End If

thanx it's solved

That will show the dialog twice though.

Should be

Code:

---

If OFD.ShowDialog = Windows.Forms.DialogResult.OK Then
    'Ok clicked
Else
    'Canceled
End If

---

Guys help, I can' t understund
I used the above code, I used three different codes, none works.

Here is another example

Select Case MessageBox.Show(MessageBoxButtons.OKCancel)
Case MsgBoxResult.Yes
'do yes stuff here
MessageBox.Show("OK")
Case MsgBoxResult.Cancel
'do cancel stuff here
MessageBox.Show("Cancel")
End Select

I press "Open" or "Cancel", and the dialogbox shows itself again and again, for 10-15 times.
It executes Messagebox, and the same again. After this it stops.
Some times (with Select-Case), it gives me MessageBox "1".
It doesn't make sence.
I traced with breakpoint, but no luck. It goes round and round.

Four things:

1) You have Option Strict Off if that code compiles, so I would suggest turning it on.
2) The first parameter of the Show method is a string containing the text you want to show, the second parameter is the title of the message box, the third parameter is where the "MessageBoxButtons.OKCancel" should go.
3) The show method returns a DialogResult, not a MsgBoxResult
4) You didn't mention where this code even is.

Try this to show your message box:

vb.net Code:

Select Case MessageBox.Show("text", _
                            "caption", _
                            MessageBoxButtons.OKCancel)
    Case Windows.Forms.DialogResult.OK
        'Run code for acceptance
    Case Windows.Forms.DialogResult.Cancel
        'Run code for cancel
End Select

The reason you are getting a message box of "1" is because (as mentioned earlier) you have Option Strict Off so there is an implicit conversion to string going on in your MessageBox.Show. The Show method is expecting a string where you put MessageBoxButtons.OKCancel so it automatically converts that to it's string representation which is "1".

Now it comes up only twice, and then it gives me an error.

Code:

---

Private Sub cmdLoad_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdLoad.Click, cmdLoad.Click
        Dim ofd As New OpenFileDialog
        Dim FileName As String
        Dim sr As StreamReader

        ofd.InitialDirectory = "::{20D04FE0-3AEA-1069-A2D8-08002B30309D}"
        ofd.Filter = "Excel Files|*.xls|Excel 2007 Files|*.xlsx"
        ofd.DefaultExt = "*.xls"
        ofd.ShowDialog()

        Select Case MessageBox.Show("text", _
                                  "MMMMMMmmmmmm", _
                                  MessageBoxButtons.OKCancel)

            Case Windows.Forms.DialogResult.OK
                'Run code for acceptance
                Try
                    MyConn.Open()
                    MyComm = New OleDbCommand("select * from [TZOKER$]", MyConn)
                    dtAdapter = New OleDbDataAdapter(MyComm)
                    dtAdapter.Fill(dtSet, "TZOKER")
                    For Each dtRow As DataRow In dtSet.Tables(0).Rows
                        'sum = dtRow("N1") + dtRow("N2") + dtRow("N3") + dtRow("N4") + dtRow("N5")
                        'code to do something with the 'sum' value
                    Next
                    dgViewSample.DataSource = dtSet.Tables(0)
                    MyConn.Close()

                Catch ex As Exception
                    MessageBox.Show(ex.Message)
                    MyConn.Close()
                Finally
                    MyConn.Close()
                    MyConn = Nothing
                    MyComm = Nothing
                    dtAdapter = Nothing
                    dtSet = Nothing
                End Try
                Exit Select
            Case Windows.Forms.DialogResult.Cancel
                'Run code for cancel
                Exit Select
        End Select

    End Sub

---

Take the close out of the catch block as it also runs in the finally block.

Code:

---

MyConn.Close()

---

What comes up twice? The dialog form?

Quote:

---

Originally Posted by RobDog888

What comes up twice? The dialog form?[/color]

---

Yes.

Hey,

Rather than explicitly call the Close method on the connection, you might think about wrapping the Connection and Command objects in Using statements, that way they will automatically closed before they go out of scope.

On another note, are you meaning to call the OpenFileDialog, and the straight away call a MessageBox, that seems quite unintuitive to me. Are you not actually wanting to call the OpenFileDialog then, based on whether the user hits Ok or Cancel perform some action?

What you are doing just now is, display the OpenFileDialog, then, regardless of what this click on there, you are then opening a MessageBox, and then doing an action based on what they press.

Is that actually what you want?

Gary

Hello,
I want to open the openfiledialog, choose an excel file, and open it.
I have done several tries with different codes, but when I choose my file,
(sometimes the data loads to datagridview, sometimes not) the openfiledialog opens again.
With the code I posted, the openfiledialog does it only two times. With other codes I just stopped counting.
I don't want the messege box, with "OK" or "Cancel".
I just want to understand what is happenning.
If I figure out I will do it other way

Edit. For some reason I cannot leave " Private Sub cmdLoad_Click", if it don't executes the hole code twice.
I placed an "Exit Sub", but....

Code:

---

              Finally
                    MyConn.Close()
                    MyConn = Nothing
                    MyComm = Nothing
                    dtAdapter = Nothing
                    dtSet = Nothing
                End Try
                Exit Select
            Case Windows.Forms.DialogResult.Cancel
                'Run code for cancel
                Exit Select
                Exit Sub
        End Select
        Exit Sub

    End Sub

---

Hey,

Let's see if we can break this down slightly for you.

This line:

Code:

---

ofd.ShowDialog()

---

Causes an OpenFileDialog to appear. When this window appears, the end user has two options.

1) Select a file to open and then hit OK, which will return a DialogResult of OK.
2) Hits the Cancel button, which will return a DialogResult of Cancel.

Now this line:

Code:

---

Select Case MessageBox.Show("text", _
                                  "MMMMMMmmmmmm", _
                                  MessageBoxButtons.OKCancel)

---

Will cause a MessageBox to appear, where the user again, has the option to hit OK and Cancel, which would return a value of DialogResult.OK or DialogResult.Cancel respectively.

You are currently switching your logic based on the result of the MessageBox.Show line, which in my opinion, based on what you have described, is not what you want to do.

Instead, you want to switch on the result of the ShowDialog line. Something like:

Code:

---

Private Sub cmdLoad_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdLoad.Click, cmdLoad.Click
        Dim ofd As New OpenFileDialog
        Dim FileName As String
        Dim sr As StreamReader

        ofd.InitialDirectory = "::{20D04FE0-3AEA-1069-A2D8-08002B30309D}"
        ofd.Filter = "Excel Files|*.xls|Excel 2007 Files|*.xlsx"
        ofd.DefaultExt = "*.xls"

        Select Case ofd.ShowDialog()

            Case Windows.Forms.DialogResult.OK
                'Run code for acceptance
                Try
                    MyConn.Open()
                    MyComm = New OleDbCommand("select * from [TZOKER$]", MyConn)
                    dtAdapter = New OleDbDataAdapter(MyComm)
                    dtAdapter.Fill(dtSet, "TZOKER")
                    For Each dtRow As DataRow In dtSet.Tables(0).Rows
                        'sum = dtRow("N1") + dtRow("N2") + dtRow("N3") + dtRow("N4") + dtRow("N5")
                        'code to do something with the 'sum' value
                    Next
                    dgViewSample.DataSource = dtSet.Tables(0)

                Catch ex As Exception
                    MessageBox.Show(ex.Message)
                Finally
                    MyConn.Close()
                    MyConn = Nothing
                    MyComm = Nothing
                    dtAdapter = Nothing
                    dtSet = Nothing
                End Try
                Exit Select
            Case Windows.Forms.DialogResult.Cancel
                'Run code for cancel
                Exit Select
        End Select

    End Sub

---

However, what is confusing me, is that you don't seem to use the excel file anywhere in the rest of the code that you have pasted. So where is your code to look at the excel spreadsheet? Have you hardcoded the link to the spreadsheet in your connection string?

Gary

TZOKER is the sheet of my excel file.
The data of the file, are loaded corectly to the datagridview.
Unfortunatly after the data are previewed to the datagridview, the openfiledialog open appears again.
This is what I can't understand. The messagebox, is another try to avoid the multiple appering of datagridview.

Hey,

Search your code for ShowDialog.

I can't see any reason, based on the code you have shown why it would be showing twice.

Gary

Neither do I.
I just deleted and write it again. I was at the begining, so it was easy.
Now it's all ok.
Thanks

Glad to hear it.

Gary