G(jw)=0=(k(jw)^2+k(jw)+k)(6w^3-9w)
how do i go about finding a value for w when k= 50, 100 and 1000 i know it will be the same method for each if u can help please do
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G(jw)=0=(k(jw)^2+k(jw)+k)(6w^3-9w)
how do i go about finding a value for w when k= 50, 100 and 1000 i know it will be the same method for each if u can help please do
Quote:
Originally Posted by vangle
Hello Vangle,
It's a homework assignment. I can't give you the answer. The work has to come from you. All I can do is guide you though. :blush:
I agree with MG, no solutions, just guidance.Quote:
Originally Posted by vangle
A good place to start is to realize that your rhand hand side can be restated if you notice that k is a multiple of all the elements in your first () area, and 3w is a multiple of all the elements of your second set of ().
So you can actually make your right hand side 3kw*(reduced quadratic)*(reduced cubic).
then since A*B*C=0 whenever A=0 or B=0 or C=0, you can produce solutions from 3kw, the reduced quadratic, and the reduced cubic.