[RESOLVED] obtain from a string

it want to obtain from a string the next result: pri004

The string:
C:\Documents and Settings\nf\Desktop\pri004_02052007.xml

how can i do it....??

thx

You mean get a certain part of a string?

Is it just this string you want, or do you want to do it with other strings aswell?

You will probably need to know a few things like, is everything in front of "pri004" always the same, is the length of substring "pri004" always the same etc...

if you know that you can use things like Mid$(), InStr() etc to get it.


For example, you could use:

Code:

---

Dim myvar As String
Dim mystring As String
Dim StartPos As Integer
mystring = "C:\Documents and Settings\nf\Desktop\pri004_02052007.xml"


StartPos = InStrRev(mystring, "\")

myvar = Mid$(mystring, StartPos + 1, 6)

---

StartPos is the position of the last "\" symbol, found using "InStrRev".
Then the Mid$() fucntion finds the part of the string that starts 1 position after StartPos (StartPos + 1) and is 6 characters long, which in this case is "pri004".

yes.

i only want to obtain pri004 from that string or the content from "pri" to the character "_"

vb Code:

Dim str As String
str = "C:\Documents and Settings\nf\Desktop\pri004_02052007.xml"
Text1.Text = Mid$(str, 38, 6)

This would be another way...
You copy and paste the path into text1 and then click this button. And if the path contains "pri" then in text2 it will show "pri" & the 3 digits after it.

vb Code:

Private Sub Command1_Click()
Dim str As String
str = Text1.Text
If InStr(1, str, "pri") > 0 Then
Text2.Text = Mid$(str, 38, 6)
End If
End Sub

vb Code:

Private Sub Command1_Click()
Dim str As String
Dim i1 as integer, i2 as integer, i3 as integer
str = Text1.Text
 
i1 = InStr(1, str, "pri") 'location of pri in the string
i2 = InStr(i1, str, "_")  'location of the first _ in the string after "pri"
i3  = i2 - i1 -1 'length of the string you want to get
If i1 > 0 And i2 > 0 And i3 > 0 Then
Text2.Text = Mid$(str, i1, i3)
End If
End Sub

(Note that this is free-hand coding, it was not tested, it could contain errors, but it should get you on the way)

thx robbedaya...it was that I was needing.
thx also all who answered me.

thx community