[RESOLVED] Reading The First Two Lines Of A Standard Textbox

I have a standard, multiline, textbox on one of my screens. A typical entry will be:

"Mr. John Smith"
12345 Cherry Lane
Boston, MA 02100

[email protected]
617-123-4567"

I need to take the address part, and store it in a variable for latter use.

Here is the problem. The address part could be two, or three lines before there is a double space with email address and phone number. It could read:

"Mr. John Smith"
No Address Listed

[email protected]
617-123-4567"

Regardless of how many lines it is, how do I get just the address part?

Pseudocode:
The @ sign is a unique identifier in the e-mail address. Search for that and count the number of lines with hard returns are in the textbox before you find it.

That way you will know exactly how many lines are in the address before the e-mail line appears.

this works.

vb Code:

Private Sub Form_Load()
    Dim strContact, strAddress
    strContact = """Mr. John Smith""" & vbCrLf & _
                 "12345 Cherry Lane" & vbCrLf & _
                 "Boston, MA 02100" & vbCrLf & vbCrLf & _
                 "[email protected]" & vbCrLf & _
                 "617-123-4567"
    MsgBox strContact
    'get the relevant information
    strAddress = Mid$(strContact, 1, InStr(1, strContact, vbCrLf & vbCrLf, vbTextCompare) - 1)
    strAddress = Mid$(strAddress, InStr(InStr(1, strAddress, """") + 1, strAddress, """", vbTextCompare) + 3, Len(strAddress))
    MsgBox """" & strAddress & """"
End Sub

when ran, the above will return this (keep in mind, the quotes around it are added on the MsgBox call to make sure no extra line breaks were there):

Code:

---

"12345 Cherry Lane
Boston, MA 02100"

---

I tested it with 1, 2 and 3 lined addresses. either way, it should work with any amount of lines. It looks for a double space and then grabs the information after the second quote before it (meaning that all of your names must have the quotes around them, otherwise it wouldn't work.. but that's possible to change, too). I manually entered the address into a variable because I didn't want to open a file or anything, but it should be fine with whatever variable you're holding your contact information in. let me know.

edit: made a quick fix to remove an extra call to Left() and removed an un-needed variable

Is there a danger that the email part could be "No email listed", would searching for VbNewline & VbNewline not be more reliable? i.e.

Code:

---

Address = Left$(Text1.Text, InStr$(Text1.Text, vbNewLine & vbNewLine) - 2)

---

Edit: did not see your post kows, soz

Here is another way:

vb Code:

Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" _
        (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, lParam As Any) As Long
Private Declare Function SendMessageStr Lib "user32" Alias "SendMessageA" _
        (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, lParam As String) As Long
Private Const EM_GETLINECOUNT = &HBA
Private Const EM_LINELENGTH = &HC1
Private Const EM_LINEINDEX = &HBB
Private Const EM_GETLINE = &HC4
 
Private Sub Command1_Click()
    Dim lngCount As Long
    Dim lngLineIndex As Long
    Dim lngLength As Long
    Dim strBuffer As String
    Dim lngIndex As Long
    
    Randomize
    
    'Get the line count
    lngCount = SendMessage(Text1.hwnd, EM_GETLINECOUNT, 0, 0)
    
    With Text1
        For lngIndex = 0 To lngCount - 1
            'Get line index of the chosen line
            lngLineIndex = SendMessage(.hwnd, EM_LINEINDEX, lngIndex, 0)
            'get line length
            lngLength = SendMessage(.hwnd, EM_LINELENGTH, lngLineIndex, 0)
'            'resize buffer
            strBuffer = Space(lngLength)
            If strBuffer = "" Then
                Exit For
            End If
'            'get line text
            Call SendMessageStr(.hwnd, EM_GETLINE, lngIndex, ByVal strBuffer)
            Debug.Print strBuffer
        Next
    End With
 
End Sub

Thank you Martin. That worked just fine with one minor alteration.

I added

Code:

---

Dim strNameAddress As String
'I substituted this line
Debug.Print strBuffer
'with
strNameAddress = strNameAddress & vbCrLf & strBuffer

---

Works great!