[2005] Trivial Percent Question

I have tried different conversions but after 45 minutes about out of ideas as to why when I run this prog I end up with 10,000.00% instead of 100.00%. As usual I searched format issues and percentage but turned up nothing relavent to me with in the first couple of pages.

Here is the code I'm using and the input i am using is 1 test to be graded and the grade is 100%.

VB Code:

Dim intCount As Integer = 1
        Dim decTotal As Decimal = 0
        Dim strNumOfTests As String
        Dim strTotalTests As String
        Dim intNumOfTests As Integer
 
 
 
        'Display input box for the number of tests
        strNumOfTests = InputBox("How many tests need to be graded? " _
        , "Number of tests", "5")
        intNumOfTests = CInt(strNumOfTests)
 
        Do Until intCount > CInt(strNumOfTests)
 
            strTotalTests = InputBox("Please enter the score for test # " _
            & intCount.ToString, "Test Scores")
            intCount += 1
            decTotal += CDec(strTotalTests)
 
        Loop
 
        'Make the If statements that are going to provide
        'a letter grade with the socre.
 
        If decTotal >= 90 Then
            lblAverageScore.Text = ("You scored " & FormatPercent(decTotal.ToString, 2) _
            & " which is an A.  Good Job!")

I know with in 5 minutes someone with far more experience then I have is going to nail this and make me look like an idiot but I'm willing to suffer the humiliation as long as I get an answer with a reason lol...

Later
Abe

VB Code:

Dim intCount As Integer = 1
        Dim decTotal As Decimal = 0
        Dim strNumOfTests As String
        Dim strTotalTests As String
        Dim intNumOfTests As Integer
 
 
 
        'Display input box for the number of tests
        strNumOfTests = InputBox("How many tests need to be graded? " _
        , "Number of tests", "5")
        intNumOfTests = CInt(strNumOfTests)
 
        Do Until intCount > CInt(strNumOfTests)
 
            strTotalTests = InputBox("Please enter the score for test # " _
            & intCount.ToString, "Test Scores")
            intCount += 1
            decTotal += CDec(strTotalTests)
 
        Loop
 
        'Make the If statements that are going to provide
        'a letter grade with the socre.
 
        If decTotal >= 90 Then
            lblAverageScore.Text = ("You scored " & FormatPercent((decTotal / 100).ToString, 2) _
            & " which is an A.  Good Job!")

Thats a pretty quick fix. Is it common to have to do division like that when dealing with percentage?

Thanks for the reply though

From the help topic for the FormatPercent function:

Quote:

---

VB Code:

Dim TestNumber As Single = 0.76
' Returns "76.00%".
Dim TestString As String = FormatPercent(TestNumber)

---

1.00 converts to 100.00%. That's how it's supposed to work and that's how it works. Always read the help. The expression RTFM applies to us who use software to write software as much as anyone else. If documentation is provided and you don't consult it then it should not be a surprise that not everything is clear.