How to pass array as return value?

Hi,

Is it possible to have a function return an array as it's return value?

Well actually, I guess it is possible to return an array because it seem to be returning the array, but I can't figure out how to use it in the calling sub.

When it the function returns the array, and I try to assign that array to another array, it won't let me.. So I guess the real question is, how do you use an array returned from a function?

Any help or examples would be appreciated..

dan

If I could see the code, I could be of more help.

Nevermind... I found the answer.. Both arrays have to be dynamic..

Thanks,

Dan

Perhaps here is THE code:

Code:

---

    '
    '--------------------------------------------------
    ' Demonstration of a Sub returning an array
    ' Simulating the Split function in VB 6
    ' Create a new project with a large textbox
    ' Set the MultiLine property of the textbox to True
    ' strMyArray() is the returned array
    '--------------------------------------------------
Option Explicit

Private Sub Form_Load()
    Dim strMyString As String
    Dim i As Long
    Dim strMyArray() As String
   
    strMyString = "This is a trial." & vbCrLf & "It is a good trial." & vbCrLf & "I like it very much" _
        & vbCrLf & "Do you like it?" & vbCrLf & "Yes, I do." & vbCrLf & "We all do, too."
   
    RetArray strMyString, vbCrLf, strMyArray()
    For i = 0 To UBound(strMyArray)
        Text1.Text = Text1.Text & strMyArray(i) & vbCrLf
    Next
   
End Sub

Private Sub RetArray(ByVal InString As String, ByVal Separator As String, RetArr() As String)
    '
    '--------------------------------------------------
    ' Sub returning an array
    '--------------------------------------------------
    Dim i As Long
    Dim j As Long
    Dim k As Long
    i = 0
    j = 1
    Do While j < Len(InString)
        k = j
        Do While j < Len(InString)
            If Mid$(InString, j, Len(Separator)) = Separator Then
                ReDim Preserve RetArr(i)
                RetArr(i) = Mid$(InString, k, j - k)
                j = j + 1
                Exit Do
            End If
            j = j + 1
        Loop
        i = i + 1
    Loop
   
End Sub

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