[RESOLVED]Timer Random Interval Question

How can i make it so my timer can randomly be off by .5 of a second either slow or fast. Ex:
Interval=10
Possible Randoms=9.5, 9.6, 9.7, 9.8, 9.9, 10, 10.1, 10.2, 10.3, 10.4, 10.5

Can anyone please help me.

P.S. the interval of the timer is specified by the user so it could be changed after they stopped the timer.

VB Code:

Option Explicit
 
Private Sub Form_Load()
Dim cnt As Long
 
   Randomize
   For cnt = 1 To 20
      Debug.Print RndVal(10, 0.5)
   Next
   Unload Me
End Sub
 
Public Function RndVal(Interval As Double, Offset As Double)
Dim dblBase As Double
   
   dblBase = Interval - Offset
   dblBase = dblBase + (2 * Offset * Rnd)
   RndVal = Round(dblBase, 1)
End Function

Can you explain how i can format that into this code:

VB Code:

Private Sub cmdStart_Click()
txtInterval = Val(txtInterval)
If ErrorCheck1() = 1 Then
Exit Sub
End If
txtText.Enabled = False
txtInterval.Enabled = False
FrmClientMain.WebBrowser1.SetFocus
Timer1.Enabled = True
Timer1.Interval = Val(txtInterval.Text) * 1000
Me.Caption = "Auto Typer [Enabled]"
cmdStop.Enabled = True
cmdStart.Enabled = False
End Sub
Private Sub cmdStop_Click()
Timer1.Enabled = False
Me.Caption = "Auto Typer [Disabled]"
cmdStop.Enabled = False
cmdStart.Enabled = True
txtText.Enabled = True
txtInterval.Enabled = True
End Sub
 
 
 
Private Sub Form_Load()
Timer1.Enabled = False
end sub
 
Private Sub Timer1_Timer()
SendKeys strColor & strEffect & txtText + ("{Enter}")
End Sub

VB Code:

Private Sub cmdStart_Click()
   txtInterval = Val(txtInterval)
   If ErrorCheck1() = 1 Then
      Exit Sub
   End If
   txtText.Enabled = False
   txtInterval.Enabled = False
   FrmClientMain.WebBrowser1.SetFocus
   Timer1.Interval = RndVal(Val(txtInterval.Text), 0.5) * 1000
   Timer1.Enabled = True
   Me.Caption = "Auto Typer [Enabled]"
   cmdStop.Enabled = True
   cmdStart.Enabled = False
End Sub
 
Public Function RndVal(Interval As Double, Offset As Double) As Double
Dim dblBase As Double
   
   dblBase = Interval - Offset
   dblBase = dblBase + (2 * Offset * Rnd)
   RndVal = Round(dblBase, 1)
End Function

Don't forget Randomize on Form_Load(). If code above throws an error try updating with

Timer1.Interval = CInt(RndVal(Val(txtInterval.Text), 0.5) * 1000)

k i just added:

VB Code:

Timer1.Interval = RndVal(Val(txtInterval.Text), 0.5) * 1000

to my timer code and it appears to be working.