Re: partial differentiation
do you understand how you differentiate like x^2 without the limit formula?( x^2 becomes 2x.)
you need to know that before you can do partial differentiation.
When it is partial differentiation you differently 3 different times for you equation.
one for x, one for y and one for z.
for the x equation you differentiate 2(x^2 +z)y + x/(z^2) treat X as the variable and treat y&z as constants.
Re: partial differentiation
Fx=(4·x·y·z^2 + 1)/z^2
Fy=2·(x^2 + z)
Fz=2·(y·z^3 - x)/z^3
Re: partial differentiation
i am fully aware how to partially differentiate functions however i am being asked to do it from 1st principles and this is what is causing me problems.
Re: partial differentiation
It works the same way as normal differentiation from first principles as the other variables are treated as constants.