how do you differentiate
2x^2 - 4xy + 3y^2 = 3 ?
cheers this is really urgent and id really appreciate a quick reply
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how do you differentiate
2x^2 - 4xy + 3y^2 = 3 ?
cheers this is really urgent and id really appreciate a quick reply
exactly what do you want to do ?
its a question and you are suppose to differentiate it and find its gradient at (2,1)
cheers
place x = 2 and y=1 and then you will get solution.
how does that help? i need to differentiate it
i think you will get it at
http://www.bbc.co.uk/education/asgur...in/index.shtml
If we can assume y is a function of x, and we are differentiating wrt x, then we make use of implicit differentiation and the product rule.
2x² - 4xy + 3y² = 3
Differentiate both sides wrt x.
4x - {4x(dy/dx) + 4y} + 6y(dy/dx) = 0
4x - 4x(dy/dx) - 4y + 6y(dy/dx) = 0
Factor out the dy/dx
(dy/dx)(6y-4x) + 4x - 4y = 0
Simplify
dy/dx = (4y-4x)/(6y-4x)
Now plug in x=2 and y=1
dy/dx|(2,1) = gradient at (2,1) = 2
If you need any concepts explained please give me a shout. AND RATE ME!!
All the best, Matt