Application.startuppath

Hello,

I want to be able to edit a file. The file will be located in the same directory as the setup.exe. However when the program is run it does work when i use the application.startupath. However, when I don't use it works ok. Can anyone explain how this should work.

Code:

---

fileMap.ExeConfigFilename = Application.StartupPath & "\CodeRed6\CodeRed_1_0_0_10\CodeRed.exe.config.deploy" 'Not work
            fileMap.ExeConfigFilename = "C:\CodeRed6\CodeRed_1_0_0_10\CodeRed.exe.config.deploy" 'Works ok

            config = ConfigurationManager.OpenMappedExeConfiguration(fileMap, ConfigurationUserLevel.None)

---

Many thanks in advance,

Steve

Did you print Application.StartupPath to confirm that it infact is: "C:\CodeRed6" ?

Is the return type for ExeConfigFilename as string?
If it is, try
fileMap.ExeConfigFilename = ".\CodeRed6\CodeRed_1_0_0_10\CodeRed.exe.config.deploy"

Surely Application.StartupPath will be returning "C:\CodeRed6\CodeRed_1_0_0_10".

According your code I assume your exe is on the

C:\

if that's true application.startuppath returns you c:\

so your path is

c:\\CodeRed6\CodeRed_1_0_0_10\CodeRed.exe.config.deploy

which returns you an error

Try that

VB Code:

If not Application.StartupPath.EndsWith("\") Then
             fileMap.ExeConfigFilename = Application.StartupPath & "\"
        End If
fileMap.ExeConfigFilename &= "CodeRed6\CodeRed_1_0_0_10\CodeRed.exe.config.deploy"

Hope this helps

JMC has given you the right answer. You need to just append it with the string of your file name.
Disregard what i wrote earlier.

Hi again

As usual JMC points on the right direction :D

Just check this tread (or have a look on the help) to know what is returning the startuppath method and concatenate the right string to get the path (or file) relative to startuppath of you application

Hello,

I thought I had this resolved.

The problem is this. I have deployed a program in the folder where the setup file is, I have a folder called CodeRed_1_0_0_10, inside that folder I have a file called CodeRed.exe.config.deploy. I want to be able to access this file.
The path is this:
C:\Deployed_4_10_06\CodeRed_1_0_0_10.

The setup.exe file is located in the Deployed_4_10_06 folder. I thought by using application.startuppath would point to this directory. However, after checking I found out that is points to this one below:

C:\Documents and Settings\yasin\Local Settings\Apps\2.0\YDBGO2AL.YA3\TOMO6HER.GJR\code..tion_53e3de40adb22891_0001.0000_adfb41cfb825f353

I thought by using this:
path = Application.StartupPath & "\CodeRed_1_0_0_11\" & "CodeRed.exe.config.deploy"

I would be able to update my file, but cannot not.

Is there a way to be able to point to the file where the setup.exe is located?

Many thanks in advance,

Steve

It looks very much like you're publishing your app using ClickOnce. One of the advantages of ClickOnce is that it has in-built auto-update functionality. You should head to MSDN and read up on ClickOnce and what it can and can't do.