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Hey there. :wave:
Can someone please help me out here...how to solve..?
|x-1| = |x-1|
I know the next step is so get rid of the absolute values so
x-1 = x-1
but then the answer will be 0??? is it correct or..??
another question:
Let A={1,3,5,7,9} and B={2,4,6,8}, C={1,2,3,4,5}
whats the answer to..
A u B n C
p.s. u: union, n:intersection
could it be {1,2,3,4,5,6,7,8,9} or {2,4} ?? :confused:
Thank you in advanceeee :bigyello:
Any and every x is a solution to |x-1|=|x-1|, not just zero.
As for your A u B n C Question - you get different answers depending on which operation you do first. For example:
(A u B) n C = ({1,3,5,7,9} u {2,4,6,8}) n {1,2,3,4,5}
= {1,2,3,4,5,6,7,8,9} n {1,2,3,4,5}
= {1,2,3,4,5}
...but...
A u (B n C) = {1,3,5,7,9} u ({2,4,6,8} n {1,2,3,4,5})
= {1,3,5,7,9} u {2,4}
= {1,2,3,4,5,7,9}
If brackets have been omited... I dunnow? Has a precedent like "do unions first" or "do the operation on the left first" been given to you? If not, the question would appear to be ambiguous...
Thanks Dross for replying I really appreciate it :D
btw urm, I still dont get why any and every x is a solution to |x-1| = |x-1| how is that possible?
Just start picking and choosing values of x to prove it.
x=5
|x-1|=|x-1|
|5-1|=|5-1|
|4|=|4|
4=4
Like that. No matter what value you put for x, you'll always come out with a solution that's true.