Grab Html Source

My program grabs the html source, and I'm not sure how to seperate it enough just to get a certain part.. here is a section of the HTML..

HTML Code:

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<tr>
<td align=right>
<font face=arial size="-1">AS&nbsp;DA:</font></td>
<td><font face=arial size="-1"><b>John</b></font>
</td>
</tr>

---

In the source of the entire page, there are many things like

HTML Code:

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<font face=arial size="-1">

---

I want to know how to find the John part somehow using the

HTML Code:

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AS DA

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part to get it. Thanks for any help.

Any help with this? Anything is greatly appreciated :)

If you want to find the text that is in the place of 'John', you could use this

VB Code:

Private Function FindName(HTML As String) As String
Dim StartPt As Integer, EndPt As Integer
 
StartPt = Instr(1, HTML, "AS&nbsp;DA:</font></td>" & vbNewLine & "<td><font face=arial size=" & Chr(34) & "-1" & Chr(34) & "><b>")
EndPt = Instr(StartPt, HTML, "</b></font>") - StartPt
 
FindName = Mid$(HTML, StartPt, EndPt)
End Function

Just call FindName() with the HTML source and it will return the name!

Plz add to my reputation if this helped!

Well, I'm not quite sure how to use this.. Maybe you can add in where i should put this and how.. or maybe just show me a simple source that downloads the html and includes that? Thanks..

You could use the Split command to seperate it into sections...

what are you tring to do... explain what you want the end result to be.

how are you getting the source? inet? webbrowser? html object?

I provided you with a function that parses out the name from the HTML.

You can use the Inet control to download the HTML source code and then send it to the FindName function which will return the name in the HTML.

Add the Microsoft Internet Transfer Control to your components (CTRL + T) and then use this code when you have a command button named Command1 and an Inet control named Inet1 on your form

VB Code:

Private Sub Command1_Click()
Dim htmlName As String
 
htmlName = FindName(Inet1.OpenURL("http://www.MY-URL-HERE.com"))
MsgBox htmlName, vbInformation
End Sub
 
Private Function FindName(HTML As String) As String
Dim StartPt As Integer, EndPt As Integer
 
StartPt = Instr(1, HTML, "AS&nbsp;DA:</font></td>" & vbNewLine & "<td><font face=arial size=" & Chr(34) & "-1" & Chr(34) & "><b>")
EndPt = Instr(StartPt, HTML, "</b></font>") - StartPt
 
FindName = Mid$(HTML, StartPt, EndPt)
End Function

This will connect to the website and then parse out the name contained in the HTML and display it in a message box

I tried doing what you said and all it does is highlight
htmlName = FindName(Inet1.OpenURL("http://www.MY-URL-HERE.com"))

oh, nevermind that was dumb of me. I never put Inet on the form.

I tried again and all it does is wait a few seconds and then says Type Mismatch and highlights this line

htmlName = FindName(Inet1.OpenURL("http://www.MY-URL-HERE.com"))

You need to replace "MY-URL-HERE" with the URL to the page that you want to get the HTML from.

If it works, please mark this thread Resolved & add to my reputation!! :)

Yes, i already did replace that :) But i still get the error 'Type Mismatch'

Please edit the code so that the first line of the FindName() function is

VB Code:

Debug.Print HTML

And then post what the HTML is so that we can help

VB Code:

Private Sub Command1_Click()
Dim htmlName As String
Debug.Print HTML
htmlName = FindName(Inet1.OpenURL("http://www.MY-URL-HERE.com"))
MsgBox htmlName, vbInformation
End Sub
 
Private Function FindName(HTML As String) As String
Dim StartPt As Integer, EndPt As Integer
 
StartPt = Instr(1, HTML, "AS&nbsp;DA:</font></td>" & vbNewLine & "<td><font face=arial size=" & Chr(34) & "-1" & Chr(34) & "><b>")
EndPt = Instr(StartPt, HTML, "</b></font>") - StartPt
 
FindName = Mid$(HTML, StartPt, EndPt)
End Function

Like that?

VB Code:

Private Sub Command1_Click()
Dim htmlName As String
htmlName = FindName(Inet1.OpenURL("http://www.MY-URL-HERE.com"))
MsgBox htmlName, vbInformation
End Sub
 
Private Function FindName(HTML As String) As String
Debug.Print HTML
Dim StartPt As Integer, EndPt As Integer
 
StartPt = Instr(1, HTML, "AS&nbsp;DA:</font></td>" & vbNewLine & "<td><font face=arial size=" & Chr(34) & "-1" & Chr(34) & "><b>")
EndPt = Instr(StartPt, HTML, "</b></font>") - StartPt
 
FindName = Mid$(HTML, StartPt, EndPt)
End Function

I tried putting it there also and it didn't make a difference..

Like this, and then come back here and tell me what it printed:

VB Code:

Private Sub Command1_Click()
Dim htmlName As String
 
htmlName = FindName(Inet1.OpenURL("http://www.MY-URL-HERE.com"))
MsgBox htmlName, vbInformation
End Sub
 
Private Function FindName(HTML As String) As String
Dim StartPt As Integer, EndPt As Integer
[b]Debug.Print HTML[/b]
 
StartPt = Instr(1, HTML, "AS&nbsp;DA:</font></td>" & vbNewLine & "<td><font face=arial size=" & Chr(34) & "-1" & Chr(34) & "><b>")
EndPt = Instr(StartPt, HTML, "</b></font>") - StartPt
 
FindName = Mid$(HTML, StartPt, EndPt)
End Function

All it did was say type mismatch and higlight the same line again..

ok then use this

VB Code:

Private Sub Command1_Click()
Dim htmlName As String
 
htmlName = FindName(Inet1.OpenURL("http://www.MY-URL-HERE.com"))
MsgBox htmlName, vbInformation
End Sub
 
Private Function FindName(HTML As String) As String
Dim StartPt As Integer, EndPt As Integer
Open "C:\DEBUG.txt" For Output As #1
Print #1, HTML
Close #1
 
StartPt = Instr(1, HTML, "AS&nbsp;DA:</font></td>" & vbNewLine & "<td><font face=arial size=" & Chr(34) & "-1" & Chr(34) & "><b>")
EndPt = Instr(StartPt, HTML, "</b></font>") - StartPt
 
FindName = Mid$(HTML, StartPt, EndPt)
End Function

And after it gives you the error go to your C:\ drive and look for a file called DEBUG.txt and post the contents of that file here
REMEMBER to change the URL to the one where your file is

It didn't even make the file.

That's very strange.
Add a breakpoint on the line that contains your URL and then step through the code using F8 to see exactly where the error occurs

Well, your code doesn't seem to work :-// Oh well, I guess..

You really don't appreciate what I've done.
I've been trying to help you

Yes, I really appreciate that. I've done everything you've said with no result. So, I guess I'm just giving up, as the code seems flawless and there's nowhere else we can take it to. Therefore, I say 'Oh Well'

add a reference to the Microsoft HTML Object Library

VB Code:

Dim HTML As New HTMLDocument
    Dim tHTML As HTMLDocument
    Dim TBL As HTMLTable
    Dim ROW As HTMLTableRow
    Dim CELL As HTMLTableCell
    Dim NextCell As Boolean
    HTML = tHTML.createDocumentFromUrl("http://www.URLHERE.com", vbNullString)
    Do Until HTML.readyState = "complete"
        DoEvents
    Loop
        
    For Each TBL In HTML.getElementsByTagName("table")
        For Each ROW In TBL.rows
        NextCell = False
            For Each CELL In ROW.cells
                Debug.Print CELL.innerText
                'this is just a guess since I cant see full source
                If NextCell Then
                    MsgBox CELL.innerText
                    NextCell = False
                    Exit For
                End If
                If CELL.innerText = "AS DA:" Then
                    NextCell = True
                End If
            Next
        Next
    Next

or.. actually Try this code:
It work a little better.. but read the note in it.. ive never tried it like that..
setting a CELL object using the cell index

VB Code:

Dim HTML As New HTMLDocument
    Dim tHTML As HTMLDocument
    Dim TBL As HTMLTable
    Dim ROW As HTMLTableRow
    Dim CELL As HTMLTableCell
    Dim CELL2 As HTMLTableCell
    HTML = tHTML.createDocumentFromUrl("http://www.URLHERE.com", vbNullString)
    Do Until HTML.readyState = "complete"
        DoEvents
    Loop
        
    For Each TBL In HTML.getElementsByTagName("table")
        For Each ROW In TBL.rows
            For Each CELL In ROW.cells
                Debug.Print CELL.innerText
                'this is just a guess since I cant see full source
                If CELL.innerText = "AS DA:" Then
                    'this code here is UNTESTED! lol..
                    'ive never tried it this way before but it
                    'might just work....
                    Set CELL2 = ROW.cells(CELL.cellIndex + 1)
                    MsgBox CELL2.innerText
                    Exit For
                End If
            Next
        Next
    Next

Maybe you could be so kind as to show me an example on where this code can be used.. or a source :-/ or something :)

try something like this ..

VB Code:

Private Sub Command1_Click()
    Dim i As String
    i = getHTMLDocument("http://www.mywebsitepage.com")
    If Len(i) Then
        i = Replace(i, "AS", Chr(&H9F) & "AS")
        Call ParseText(i)
        'Text1 = i
    End If
End Sub
 
'// ADD SENTENCES TO TEXT BOX
Private Sub ParseText(ByVal myString As String)
    Dim sArray() As String
    Dim sTemp As String
    Dim sLine As String
    Dim iLine As Integer
    Dim e As Integer
    sArray = Split(myString, Chr(&H9F))       ' SPLIT UP THE SENTENCES
    iLine = 0
    For e = 0 To UBound(sArray)             ' LOOP THROUGH EACH ONE
        sTemp = Trim$(sArray(e))            ' GET RID OF SPACES AT ENDS
        If Len(sTemp) > 0 Then              ' IF THERE IS MORE THAN 1 LETTER
            iLine = iLine + 1               ' ADD NUMBERS TO LINES
            sLine = Left(sTemp, InStr(sTemp, ":"))
            If Len(sLine) Then
                Text1 = Text1 & "LINE " & iLine & ": " & sLine & vbCrLf
                Text1 = Text1 & "RESULTS: " & Replace(sTemp, sLine, "") & vbCrLf & vbCrLf
            End If
        End If
    Next e
End Sub
 
'// HTMLDOC *** GET TEXT FROM WEB PAGE **** REFERENCE REQUIRED
Private Function getHTMLDocument(ByVal strUrl As String) As String
    Dim HTML As New HTMLDocument
    Dim DOC As HTMLDocument
    Set DOC = HTML.createDocumentFromUrl(strUrl, vbNullString)
    Do While DOC.readyState <> "complete"
        DoEvents
    Loop
    getHTMLDocument = DOC.documentElement.innerText
End Function

Ok, all that did was take the text that is actually shown on the web page.. how am i supposed to find the 'John' part?

I'm guessing I do something like this..

If temp(b) = "As Da:" Then temp (b + 1) And List1.AddItem(List1.ListIndex)

I don't know :(..

Ok...well to find 'John' in that, use this once you have the HTML saved in a String variable. (Let's assume that the variable is called htmlStore, and it's public)

VB Code:

Private Function FindResult()
 
Dim HolderOne() as String
Dim HolderTwo() as String
Dim Result As String
 
HolderOne() = Split(htmlStore, "&nbsp;DA:</font></td>
<td><font face=arial size="-1"><b>")
 
HolderTwo() = Split(HolderOne(1), "</b></font>")
 
Result = HolderTwo(0)
MsgBox Result
 
End Function

All this does is VERY SIMPLY find whatever the name is in the HTML. So, here is what you are going to do once you download the HTML using the INET control:

STORE THE HTML IN A PUBLIC STRING NAMED htmlStore

Then, call this function to find whatever the name is in the document.

That's the easy part. If you don't get it then give up.

Rate it if it works!

When you told me to split this...

HolderOne() = Split(htmlStore, "&nbsp;DA:</font></td>
<td><font face=arial size="-1"><b>")


VB won't let you split that, i just pasted it in and it turned RED.

Quote:

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That's the easy part. If you don't get it then give up.

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Also, Thanks for the encouragement.

Even when i tried what was used in the first post..

HolderOne() = Split(htmlStore, "Real&nbsp;Name:</font></td>" & vbNewLine & "<td><font face=arial size=" & Chr(34) & "-1" & Chr(34) & "><b>")

It just highlights the HolderTwo line and says subscript out of range.. The easy part eh?

You can adapt my 'FindName' function from above to get the 'John' part out of the html

VB Code:

Public Sub getName()
On Error Resume Next
 
'Get the text between search strings.
    Dim sSource As String
    Dim sFindStart As String, sFindEnd As String
    Dim lStart As Long, lEnd As Long
     sSource = Inet1.openUrl ("HTTP://www.yourwebsitehere.com")
 
 
            'Initialize variables.
        lStart = 1
        lEnd = 1
        sFindStart = "AS&nbsp;DA:</font></td><td><font face=arial size=" & Chr$(34) & "-1" & Chr$(34) & "><b>"
        sFindEnd = "</b></font>"
        
    'Get the document text.
 
    
    'Find the start position.
        lStart = InStr(lStart, sSource, sFindStart, vbTextCompare)
        
        'Find the end postion only if the start text is found.
            If lStart Then
            
                'Add the length of the search text.
                    lStart = lStart + Len(sFindStart)
                
                lEnd = InStr(lStart, sSource, sFindEnd, vbTextCompare)
                
                If lEnd > lStart Then
                    Name =  Mid$(sSource, lStart, lEnd - lStart)
                   
                Else
                    Debug.Print "name End text not found."
                End If
                
            Else
            
                Debug.Print "name Text not found."
                
            End If
End Sub

Add that code to your project, change the url in the Inet1.openurl line to your site, obviously you need to add an Inet control to your project. What it does is searches for the html directly in front of and following the text you wish to find and returns what is between.

The error type mismatch was likely coming from the vbnewline in the code by shirazamod, I am betting it didn't find the start text. The mid function will error if it returns 0 for the start, that is why you need to initialize the variables and allow for the possibility that it won't find the start or finish points.

Quote:

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Originally Posted by k0zz

I'm guessing I do something like this..

If temp(b) = "As Da:" Then temp (b + 1) And List1.AddItem(List1.ListIndex)

I don't know :(..

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the results line is the part that gets the name.

Text1 = Text1 & "RESULTS: " & Replace(sTemp, sLine, "") & vbCrLf & vbCrLf