text with layout

I have posted under traditional VB since that is what I am using but it seems this could be viewed as an office problem
http://www.vbforums.com/showthread.p...49#post2526649

Word 2003 removed the save as "text with layout"
option which is what I used.
I am looking to take an RTF file from word and make a text file that has only spaces and CR/LF
BUT
I need to save the layout so an indented paragraph should have spaces added to the line so that it lines up like it used to.

do you want to write code to do this or just a simple solution, which could be put into code anyway?

find all tabs and replace with spaces (however many spaces to make it look right). if you have tabs in other parts of your document it may give a problem, but that could filtered by sections

pete

I guess I am open to anything right now.
Replacing the tabs is the simple part.
the thing I can't get my head around is the indented paragraphs.

help, I am trying to work with paraformat2 and I am having a hard time.

here is the code I am dealing with.
Command1_Click() gets me the text just fine but it looses the indenting.
it looked like paraformat2 could query the line and tell me its indent.
with the text, and the indent I would be able to pad the front of the text with spaces.

can someone help me with the paraformat2 type declaration and how to use the EM_GETPARAFORMAT sendmessage?

thanks

VB Code:

Private Declare Function SendMessageAsLong Lib "user32" Alias "SendMessageA" (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, ByVal lParam As Long) As Long
Private Declare Function SendMessageAsString Lib "user32" Alias "SendMessageA" (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, ByVal lParam As String) As Long
Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, lParam As Any) As Long
Const WM_USER = &H400
Const EM_GETPARAFORMAT = (WM_USER + 61)
Const EM_SETPARAFORMAT = (WM_USER + 71)
Const MAX_TAB_STOPS = 32&
Const PFM_LINESPACING = &H100&
Const EM_GETLINE = &HC4
Const EM_GETLINECOUNT = 186&
Const EM_GETWORDBREAKPROC = &HD1
Const EM_LIMITTEXT = &HC5
Private Type PARAFORMAT2
    cbSize As Integer
    wPad1 As Integer
    dwMask As Long
    wNumbering As Integer
    wReserved As Integer
    dxStartIndent As Long
    dxRightIndent As Long
    dxOffset As Long
    wAlignment As Integer
    cTabCount As Integer
    lTabStops(0 To MAX_TAB_STOPS - 1) As Long
    dySpaceBefore As Long          ' Vertical spacing before para
    dySpaceAfter As Long           ' Vertical spacing after para
    dyLineSpacing As Long          ' Line spacing depending on Rule
    sStyle As Integer              ' Style handle
    bLineSpacingRule As Byte       ' Rule for line spacing
    bCRC As Byte                   ' Reserved for CRC for rapid searching
    wShadingWeight As Integer      ' Shading in hundredths of a per cent
    wShadingStyle As Integer       ' Nibble 0: style, 1: cfpat, 2: cbpat
    wNumberingStart As Integer     ' Starting value for numbering
    wNumberingStyle As Integer     ' Alignment, roman/arabic, (), ), .,     etc.
    wNumberingTab As Integer       ' Space between 1st indent and 1st-line text
    wBorderSpace As Integer        ' Space between border and text(twips)
    wBorderWidth As Integer        ' Border pen width (twips)
    wBorders As Integer            ' Byte 0: bits specify which borders; Nibble 2: border style; 3: color                                     index*/
End Type
Private Sub Command2_Click()
Dim parastruct As PARAFORMAT2
With parastruct
    .cbSize = Len(para)
    .dwMask = PFM_LEFTINDENT
End With
SendMessage RichTextBox1.hwnd, EM_GETPARAFORMAT, ByVal 0&, parastruct
MsgBox "what"
End Sub
 
 
Private Sub Command1_Click()
    Dim iFileNummer                     As Integer
    Dim lCount                          As Long
    Dim lLineCounter                    As Long
    Dim x                               As Long
    Dim Buffer                          As String
    
    iFileNummer = FreeFile
    Open "c:\temp\export.txt" For Output As #iFileNummer
    lCount = SendMessageAsLong(RichTextBox1.hwnd, EM_GETLINECOUNT, 0&, 0&)
    For lLineCounter = 0 To lCount
        j
        Buffer = Space$(255)
        x = SendMessageAsString(RichTextBox1.hwnd, EM_GETLINE, lLineCounter, Buffer)
        Print #iFileNummer, Left$(Buffer, x)
    Next lLineCounter
    Close #iFileNummer
End Sub

hello, any ideas?

send me a sample document and i will look at it

pete

take a look at the attached.

taking a look at the api call, I would need to index the call so that I get the format of the current line I am dealing with.

any idea on how to get that set or setup?

maybe this api is not the way to go.
My real intent is to find out how a paragraph is indented so that I can add spaces to the text.

For those who PM me,
I can get the TEXT. My goal is getting it formatted with spaces and hard returns so it looks close to the original.

being one space off won't kill me, so if something is indented .2" and 4 spaces is a little short, that is OK, but I want to know if it is .2" or .4" of indent.. that is the real trick..

thanks

VB Code:

For Each p In ActiveDocument.Paragraphs
n = ActiveDocument.Name
    ind = p.LeftIndent
    hang = p.CharacterUnitLeftIndent
'    for each
Next

left indent returned 18 on the first paragraphs of the sample file, i believe that is 18 points, ¼".

i was looking at that, but hadn't decided yet what could be done with it as the paragraph is a single line in the RTF file, before word wrapping

the line indent in the RTF code (/li360) varied a lot, but shows as 360 in many instances, which also converts to ¼"

you can read the RTF code for each paragraph, then apply that as you get each paragraph of text.

pete

edit: in vb you can use textwidth to make the number of spaces very accurate for the length of the gap you want to insert

VB Code:

strl = (leftindent) / TextWidth(" ")
mystr = Space(strl)

remember that the font face and size will change the textwidth, so set the font of the form or a picture box to the required font if it is not a same font, unless you are printing it direct, then use the printers textwidth

here is code that reads your sample file and saves it as text file with spaces to format the document with indents.

so far i have not done anything to word wrap the longer lines of text, but that will not be too hard to do, just not tonight, try the code on seversl files, see how many bugs in it.

VB Code:

Private Sub Command1_Click()
Dim i As Integer, pos As Integer, mytest, pos1 As Integer
 
Dim li As Integer, strfi As String, f1 As Integer, arrfi() As String, pard As Boolean
Dim tlen As Integer, myind As String
 
 
f1 = FreeFile
Open "spec.rtf" For Input As f1
    strfi = Input(LOF(f1), #f1)
Close f1
pard = False
arrfi = Split(strfi, vbNewLine)
 
Open "spec.txt" For Output As f1
For i = 0 To UBound(arrfi)
    If pard = False Then
        If InStr(1, arrfi(i), "\pard") = 0 Then
            GoTo notyet
            Else: pard = True
        End If
    End If
    pos = InStr(1, arrfi(i), "\li")
        If Not pos = 0 Then
            pos1 = InStr(pos + 3, arrfi(i), "\") - pos - 3
            mytest = Mid(arrfi(i), pos + 3, pos1)
            If Left(mytest, 1) = "n" Then
                pos = InStr(pos + 1, arrfi(i), "\li")
                If Not pos = 0 Then
                    pos1 = InStr(pos + 3, arrfi(i), "\") - pos - 3
                    mytest = Mid(arrfi(i), pos + 3, pos1)
                End If
            End If
            li = Val(mytest)
'            Debug.Print li, i
        End If
    mytest = ""
    tlen = li / 4 / TextWidth(" ")
    myind = Space(tlen)
    pos = InStrRev(arrfi(i), "\")
    If pos = 0 Then
        mytest = arrfi(i)
        Else
        pos = InStr(pos + 1, arrfi(i), " ")
        If pos = 0 Then Stop
        pos1 = Len(arrfi(i))
        If Not Len(arrfi(i)) = pos Then mytest = Right(arrfi(i), Len(arrfi(i)) - pos)
    End If
    If mytest = "" Or mytest = "}}" Then mytest = " "
    If Left(mytest, 1) = "{" Then mytest = Right(mytest, Len(mytest) - 1)
notyet:
    If Not mytest = "" Then Print #f1, myind & mytest 'mytest = "not yet"
    
Next
Close f1
 
Exit Sub

pete

here is some updated code to word wrap the lines, it is not perfect, but yopushould be able to play around with it to make any improvements needed

pete

VB Code:

Private Function wordwrap(mystring As String, indent As String)
Dim arrwords() As String, i As Integer, newstr As String, longstr As String
arrwords = Split(mystring)
newstr = indent
For i = 0 To UBound(arrwords)
    If Not TextWidth(newstr & arrwords(i)) > 6300 Then
        newstr = newstr & arrwords(i) & Space(1)
    Else
    If longstr = "" Then
        longstr = newstr
            Else
            longstr = longstr & vbNewLine & indent & newstr
            End If
            newstr = indent & arrwords(i) & Space(1)
            
    End If
Next
If longstr = "" Then
    wordwrap = newstr
    Else: wordwrap = longstr & vbNewLine & indent & indent & newstr
End If
End Function
Private Sub Command1_Click()
Dim i As Integer, pos As Integer, mytest As String, pos1 As Integer
 
Dim li As Integer, strfi As String, f1 As Integer, arrfi() As String, pard As Boolean
Dim tlen As Integer, myind As String
 
 
f1 = FreeFile
Open "spec.rtf" For Input As f1
    strfi = Input(LOF(f1), #f1)
Close f1
pard = False
arrfi = Split(strfi, vbNewLine)
 
Open "spec.txt" For Output As f1
For i = 0 To UBound(arrfi)
    If pard = False Then
        If InStr(1, arrfi(i), "\pard") = 0 Then
            GoTo notyet
            Else: pard = True
        End If
    End If
    If Not i = UBound(arrfi) Then
        If Not Left(arrfi(i + 1), 1) = "\" Then
            arrfi(i) = arrfi(i) & arrfi(i + 1)
            arrfi(i + 1) = ""
        End If
    End If
    pos = InStr(1, arrfi(i), "\li")
        If Not pos = 0 Then
            pos1 = InStr(pos + 3, arrfi(i), "\") - pos - 3
            mytest = Mid(arrfi(i), pos + 3, pos1)
            If Left(mytest, 1) = "n" Then
                pos = InStr(pos + 1, arrfi(i), "\li")
                If Not pos = 0 Then
                    pos1 = InStr(pos + 3, arrfi(i), "\") - pos - 3
                    mytest = Mid(arrfi(i), pos + 3, pos1)
                End If
            End If
            li = Val(mytest)
'            Debug.Print li, i
        End If
    mytest = ""
    tlen = li / 4 / TextWidth(" ")
    myind = Space(tlen)
    pos = InStrRev(arrfi(i), "\")
    If pos = 0 Then
        mytest = arrfi(i)
        Else
        pos = InStr(pos + 1, arrfi(i), " ")
        If pos = 0 Then Stop
        pos1 = Len(arrfi(i))
        If Not Len(arrfi(i)) = pos Then mytest = Right(arrfi(i), Len(arrfi(i)) - pos)
    End If
    If mytest = "" Or mytest = "}}" Then mytest = " "
    If Left(mytest, 1) = "{" Then mytest = Right(mytest, Len(mytest) - 1)
'    If i = 37 Then Stop
        mytest = wordwrap(mytest, myind)
notyet:
    If Not mytest = "" Then Print #f1, mytest  'mytest = "not yet"
    
Next
Close f1
Shell "notepad.exe spec.txt"
Stop
Exit Sub

Thanks for all that you have done.
I will have to wait until I get back in the office to test it.

again, I apprecite your help

I have run the code and this is what I am getting

Code:

---

 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
Fire Alarm Equipment Specifications
>080<
Manual Pull Station
   
  box cover at 44" AFF.
 
 
>090<
15 Candela Fire Alarm Horn/Strobe
   
  Simplex #4903-9428 Audible/Visible unit (15 Candela, 1 Hz flash rate, off-white w/Red
      "FIRE").  Mount on recessed 4" square box with bottom of unit at 80" AFF.
 
 
>093<
110 Candela Fire Alarm Horn/Strobe
   
  Simplex #4903-9430 Audible/Visible unit (110 Candela, 1 Hz flash rate, off-white w/Red
      "FIRE").  Mount on recessed 4" square box with bottom of unit at 80" AFF.
 
 
>095<
Fire Alarm Horn only
   
  Simplex #4901-9820 Horn with 4905-9989 cover (White).
 
Mount on recessed 4" square box with bottom of unit at 80" AFF.
 
>100<
15 Candela Fire Alarm Strobe only
   
  Simplex #4904-9342 Visible Only Unit (15 Candela, 1 Hz flash rate, off-white w/Red
    "FIRE").  Mount on recessed 4" square box with single gang plaster ring with bottom of
      the unit at 80" AFF.
 
 
>105<
110 Candela Fire Alarm Strobe only
   
  Simplex #4904-9344 Visible Only Unit (110 Candela, 1 Hz flash rate, off-white w/Red
    "FIRE").  Mount on recessed 4" square box with single gang plaster ring with bottom of
      the unit at 80" AFF.
 
 
>110<
Photoelectric Smoke Detector
   
  Simplex #4098-9601 detector w/ #4098-9788 base, surface mount on suspended
      ceiling on 4" octagonal box.
 
 
>120<
Photoelectric Duct Smoke Detector
   
  Simplex #4098-9686 smoke/housing & appropriate sampling tube, mount w/ sampling
      tube in air stream or air duct.
 
 
>130<
Photoelectric Smoke Detector w/ Aux. DPDT Relay Contacts
   
  Simplex #4098-9601 detector w/ #4098-9682 base with relay, surface mount on
      suspended ceiling on 4" octagonal box.
 
 
>140<
Heat Detector
   
  Simplex #4098-9613 detector w/ #4098-9682 base rate of rise (15 degree F/min) and
    fixed temperature (136 degree F) heat detector. Mount on recessed 4" octagonal box in
      ceiling.
 
>150<
Fixed Temperature Heat Detector
   
  Simplex #4098-9612 detector w/ #4098-9682 base 135 degree  F fixed point detector
      w/2 normally open contacts. Mount on 4" octagonal box.
 
>160<
Remote Test / Alarm Indicator Station
   
  box cover at 54" AFF.
 
>170<
Smoke Damper
   
  damper motor.  Wired by EC.
 
>180<
Sprinkler Flow Switch
   
  SPDT contacts provided by Sprinkler Contractor, wired by EC.
 
>190<
Sprinkler Tamper Switch
   
  Switch w/normally closed contacts provided by Sprinkler Contractor, wired by EC.
 
>200<
Fire/Smoke Door
   
  link (re-usable), wired by EC.
 
>210<
Fire Alarm Control & Annunciator Panel Specifications
>220<
Simplex #4004 series, 24V DC Fire Alarm with:
>230<
Simplex #4005 series, 24V DC Fire Alarm with:
>260<
4 hour battery
>270<
24 hour battery monitoring plus 5 minute alarm
>280<
Provision for 24VDC reverse polarity city fire dept. signal module
>285<
LED annunciator panel.
>290<
status command unit (SCU) remote annunciator panel.
>300<
Fire Alarm Zones
>310<
 
1st Floor
2nd Floor
3rd Floor
Sprinkler Flow Switches
Spare
Spare
Spare
Spare
 
>320<
 
Spare
Spare
Spare
Spare
Spare
Spare
Spare
Spare
 
>330<
 
Spare
Spare
Spare
Spare
Spare
Spare
Spare
Spare
 
>340<
 
Spare
Spare
Spare
Spare
Spare
Spare
Spare
Spare
 
>350<
See Details on Sheet E7
>000<

---

what I see is the first line of indented text gets whacked and the second line of indented text gets double indent.


thanks for all you have done.

i wrote this code in word, with your file already open, gave great result

VB Code:

Sub formatrtf()
 
Dim p As Paragraph
 
For Each p In ActiveDocument.Paragraphs
    If p.LeftIndent > 0 Or p.FirstLineIndent > 0 Then
    mystring = mystring & Space(3)
    
    End If
    If Len(p.Range.Text) > 65 Then
    thisp = wordwrap(p.Range.Text, 65)
    Else: thisp = p.Range.Text
    End If
    mystring = mystring & thisp & vbNewLine
 
Next
 
Open "spec.txt" For Output As 1
    Print #1, mystring
Close 1
 
End Sub
Private Function wordwrap(mystring As String, chars As Long)
Dim arrwords() As String, i As Integer, newstr As String, longstr As String
arrwords = Split(mystring)
'newstr = indent
 
For i = 0 To UBound(arrwords)
    If Not Len(newstr & arrwords(i)) > chars Then
        newstr = newstr & arrwords(i) & Space(1)
    Else
    If longstr = "" Then
        longstr = newstr
            Else
            longstr = longstr & vbNewLine & Space(3) & newstr
            End If
            newstr = arrwords(i) & Space(1)
            
    End If
Next
    wordwrap = longstr & vbNewLine & Space(3) & newstr
End Function