It's possible mathematics in a ListBox?

Hi All :wave:

It's possible adding a different of values in a ListBox. For example. I have in a ListBox some a value 5 then I add other the value 3. If will be the same of item this should add only an value, and the name of item should be the same also the quantity of thing should stay the same.

e.g.

I have an item:

Fish 5

I want to add:

Fish 3

it should still be only 1st thing, but only quantity should change, it's possible something this? :confused:

I would have then:

Fish 8

Thanks in advance

sure.. basically loop thru the list box.. looking for a match of the word.. then add numbers

VB Code:

Private Sub AddToList(sItem As String)
Dim tmp() As String
Dim iTmp() As String
iTmp = Split(sItem, " ")
For x = 0 To List1.ListCount - 1
    tmp = Split(List1.List(x), " ")
    If tmp(0) = iTmp(0) Then
        List1.List(x) = tmp(0) & " " & (Val(tmp(1)) + Val(iTmp(1)))
        Exit Sub
    End If
Next
 
End Sub
 
Private Sub Command1_Click()
    AddToList "Fish 7"
End Sub
 
Private Sub Form_Load()
    List1.AddItem "Fish 5"
    List1.AddItem "Cars 3"
End Sub

Something like the following may work for you:

VB Code:

Private Sub Command1_Click()
'============================
Dim iOldQty%, iNewQty%, i%
Dim strWhat$
Dim blnExist As Boolean
 
    iNewQty = CInt(txtQty.Text) 'txtQty is a textbox that user enters new quantity
    strWhat = "Fish "
    
    For i = 0 To List1.ListCount - 1
        If InStr(1, List1.List(i), strWhat) > 0 Then
            iOldQty = CInt(Mid(List1.List(i), InStr(1, List1.List(i), strWhat) + Len(strWhat)))
            List1.List(i) = "Fish " & iOldQty + iNewQty
            blnExist = True
            Exit For
        End If
    Next i
    
    If Not blnExist Then
        List1.AddItem "Fish " & iNewQty
    End If
 
End Sub

Hi all :wave:

Static: thanks for your solved, your code it works nicely...but nothing writes into a ListBox if I don't add any number to each a word or I write a new the word.

Rhinobull: I thank you very also. Also your code it works nicely. I added several details. I try to solve now one small an problem.

How to make that this code will be not distinguish small and large letters?

When I write a word with small of letter then this code will treat such the word as new the word and it adds a new an item.

this code is such now:

VB Code:

Option Explicit
 
Private Sub Command1_Click()
'============================
Dim iOldQty%, iNewQty%, i%
Dim strWhat$
Dim blnExist As Boolean
 
    iNewQty = CInt(txtQty.Text) '<<< txtQty is a textbox that user enters new quantity
    strWhat = txtName.Text      '<<< txtName is a textbox that user enters new name
    
    For i = 0 To List1.ListCount - 1
        If InStr(1, List1.List(i), strWhat) > 0 Then
            iOldQty = CInt(Mid(List1.List(i), InStr(1, List1.List(i), strWhat) + Len(strWhat)))
            List1.List(i) = txtName.Text & " " & iOldQty + iNewQty '<<< I added a bit of space betveen word and number
            blnExist = True
            Exit For
        End If
    Next i
    
    If Not blnExist Then
        List1.AddItem txtName.Text & " " & iNewQty '<<< I added space here also
    End If
 
End Sub
 
Private Sub Form_Load() '<<< I used two line from Staic's code (Static, sorry..)
    List1.AddItem "Fish 5"
    List1.AddItem "Cars 3"
End Sub

So, how to make?
Thanks in advance

Quote:

---

Originally Posted by Tamgovb

...When I write a word with small of letter then this code will treat such the word as new the word and it adds a new an item....

---

Just convert text to Upper or Lower case:

VB Code:

'change this line
If InStr(1, List1.List(i), strWhat) > 0 Then
 
'to this
If InStr(1, [B]LCase[/B](List1.List(i)), [B]LCase[/B](strWhat)) > 0 Then

Thanks Rhino, sorry, but I get "run-time error '13' " Type mismatch in this line:

VB Code:

iOldQty = CInt(Mid(List1.List(i), InStr(1, List1.List(i), strWhat) + Len(strWhat)))

though that conversion in this line it's done

I don't know what to do.
Thanks

Work fine for me...

However, if txtQty or txtName textbox is empty then you will get that error so you need some validation.
You can do something like the following:

VB Code:

[B]If IsNumeric(txtQty.Text) = False Or Trim(txtName.Text) = "" Then Exit Sub[/B]
    
    iNewQty = CInt(txtQty.Text) '<<< txtQty is a textbox that user enters new quantity
    strWhat = txtName.Text

Hi All, hi Rhino :wave:

Sorry, long I was absent

I get this error when I try to write each word with other a first the character than was written in a ListBox.
BTW: Always is written something in every textboxes - never is no empty

e.g.

if is written there in a ListBox:

Cars

And I will be a write in a txtName

cars

then I get this error - I hope that you understand me

if I wrote in a txtName

Cars

Then it's okay. :sick: Hmmm, let's say….

Obviously in a txtQty it's written always some number - is not empty

Thanks in advance

Hi All

still not solved this problem

did u use Rhino's code Lcase() in the compare?

either that or use

Instr(1,string1,string2,vbTextCompare)

that will ignore case....

Hmm... sincerely saying - I don't know how to apply this vbTextCompare (exactly in which a line - I never used from this)
thanks

Hi all

Someone you know, how to make? Please, help me.

thanks in advance

VB Code:

If InStr(1, LCase(List1.List(i)), LCase(strWhat),vbTextCompare) > 0 Then

Thanks, this problem it's solved

I made it so:

I added yet one a variable

VB Code:

Dim Find As Integer

Next I rebuilt record a bit

VB Code:

For i = 0 To List1.ListCount - 1
      If InStr(1, List1.List(i), strWhat, vbTextCompare) > 0 Then
         Find = InStrRev(List1.List(i), " ")
         If Find <> 0 Then
            List1.List(i) = Left$(List1.List(i), Find) & Val(Right$(List1.List(i), Len(List1.List(i)) - Find)) + Val(txtQty)
            blnExist = True
            Exit For
         End If
      End If
   Next
   
   If Not blnExist Then List1.AddItem txtName.Text & " " & iNewQty
End Sub

It work fine for me,

Thanks All