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I am trying to make this fireworks effect in a language called Turing. It has gr predefined procedures like drawdot, drawcircle, drawarc etc. The syntax doesn't matter at all. I would like to know if anyone knows the logic or the basic steps on how to do it. you might want ot look into trignometry and radians of a circle. PLEASE HELP. This is for a school assignment
Try using a particle system.
You get the idea he can't be bothered to learn it so he's telling us we need to learn trignometry and radians to help him. No offence tho, just found it funny :D :D :D, my sense of humour is twisted :D :) :D :) :D :) :D.Quote:
Originally posted by royjacob
you might want ot look into trignometry and radians of a circle.
I say that in confidence because I check his profile and he hasn't posted anything for two years :D
:D
The funny thing is that DX has a fireworks demo in its SDK. :D
DX isn't supported by the language he wants to use....
S'pose he could use some of the consepts though.
Dx 7 or Dx8 and would it have been out when he posted?? :cool: :) :o :p ;) :rolleyes: :cool: :eek: (I've gone mad :D)
DX 6 should have been out.
I had a look at the Turing web site, and it doesn't support any kind of components/references.
Hehe, do you like my little dude: http://www.vbforums.com/attachment.p...postid=1491246
lol - already i can think of countless situations where it can be used to express emotions that cannot be expressed in words. :)
I'm gona keep a copy of the link on my PC (with easy access) so I can use it like a smilie in other posts :D.
A cunning plan.
This guys gona get a shock if/when he logs on and sees whats happened to his thread ;) :p.
lol, yeah.
loop through radius (from 0 to whatever) and inside that loop, loop through pi*2 (thats 360 degrees in radians) and set the pixels in:
x= cos(current_degree)*raduis
y= sin(current_degree)*raduis
then do some small random so they dont move in a staight line.
then add gravity...do a search to find out how.
I found a easy way to remember the link for the little dude, he's now in my signiture :D :D :D.
hehe! thats nice! :)
Well, at least his post is answered. :D
Thats if he'll be able to find the answer tho all the off-topic chat http://www.vbforums.com/attachment.p...postid=1491246
If he wants it, he'll find it. ;)
If it is someone else who wants it, he'll probably post the question again. :)