If we used a different numberin system and 2 + 2 = 3
wot would 3 + 3 = ?
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If we used a different numberin system and 2 + 2 = 3
wot would 3 + 3 = ?
Well, as x = 2 and y = 2 in your first equation, with x+y = 3. Which simply doesn't work. To convert to current standards wouldn't we simply use
x + y - 1 = n ?
In other words 3 + 3 = 5
but no that would not work, seeing that there could be other rules that apply, in order to accurately assert the answer two sample problems and solutions would have to be provided...
It's not mind boggling, merely senseless :)
:sick: + :lol: =http://www.vbforums.com/images/ieimages/2006/03/1.gif
3+3 = 8
6 + (7 - EN) = 6 + sev = six + sev = sex
- ØØ -
Sex = One before sivven.
In Swedish, 6 is spelled sex...:)
Yes we know that.
And with all those gorgeous blondes in Sweden, I'm surprised you people didn't name more numbers after procreation activities..
That's because the mathematicians are blonde too. :afrog:
we should change the english spelling of six to sex.
I would have loved that when i was a little kid. Gigglin every maths lesson.
HEHEHE... sex..... HEHEHEHE
3+3 = 2*3
2 + 3 = 5
Bingo?
Boggle, wasn't that a very stupid game? :D
Yep, very fun though, especially after a large meal when everyone is tired and just want to sleep. Then you shake the game and the dice type things make a huge racket. PERFECT :DQuote:
Originally Posted by vbcode1980
Quote:
Originally Posted by vbcode1980
Blond is not gorgeous, it is boring...now take a look at this...this is gorgeous..:)
http://www.noteme.com/images/norway_party/DSC_0061.JPG
we never said brunette wasn't gorgeous as well...
I'm not a fan of facial hair, but whatever works for you I guess! :sick:
The girl aint bad tho. ;)
You are using binary addition on 2^x numbers.Quote:
Originally Posted by greythej
2^2 + 2^2 = 2^3
where X indicates the significant bit, from right to left. With this method, you can also see 2+2 is indeed 3 via the following:
10 + 10 = 100
So, what is 3+3?
4.
(100 + 100 = 1000)
What HE said!Quote:
Originally Posted by wossname
:D
it can be a number of things, especially if the operators dont mean the same... if the operators are the same, then its simply...
3 + 3 = 2 + 2 + 2 + 2
Now gimmie a cookie.....
Quote:
Originally Posted by si_the_geek
I'm in love...:)
:lol:Quote:
Originally Posted by NoteMe
:ehh:
:confused:
:eek2:
New idea: if 2+2=3, then we see that this Retarded Number System™ has some logic. Using the new rules of the Retarded Number System™, the plus operation (+) may actually mean x+(y/2)=n
In which case, 3+3 in the Retarded Number System™ will be 3+(3/2)=4.5
Let's make more (fun?) rules for the Retarded Number System™!
(And yes, Retarded Number System™ is Trademarked. To me. Meh :P)
New rule: Minus Operation: x-(y*2)=n
so 2-2 = -2. Simple, eh?
good work ajames.
i especially like the name...
RNS :) Great work Ajames.
Oi! ™ please!
(Yay, my work is credited at last!)
3 + 3= #^2
Quote:
Originally Posted by si_the_geek
I think that was the only sane thing to say in that situation..:)
q
ajames: I went to the liberty of coding your revolutionary RNS system (and added * and / operators for completeness).
Perfectly sound in theory...
PHP Code:using System;
using System.Collections.Generic;
using System.Text;
namespace RNS
{
class Program
{
static void Main( string[] args )
{
RetardedNumber poop = new RetardedNumber( 50 );
RetardedNumber fart = new RetardedNumber( 3 );
Console.WriteLine(string.Format("{0} + {1} = {2}",poop, fart, [B]poop + fart[/B] ));
Console.WriteLine(string.Format("{0} - {1} = {2}",poop, fart, [B]poop - fart[/B] ));
Console.WriteLine(string.Format("{0} * {1} = {2}",poop, fart, [B]poop * fart[/B] ));
Console.WriteLine(string.Format("{0} / {1} = {2}",poop, fart, [B]poop / fart[/B] ));
Console.ReadLine();
}
}
public struct RetardedNumber
{
private double _value;
public RetardedNumber( double value )
{
_value = value;
}
public static RetardedNumber operator +( RetardedNumber x, RetardedNumber y )
{
return new RetardedNumber( x._value + (y._value / 2) );
}
public static RetardedNumber operator -( RetardedNumber x, RetardedNumber y )
{
return new RetardedNumber( x._value - (y._value * 2) );
}
public static RetardedNumber operator *( RetardedNumber x, RetardedNumber y )
{
return new RetardedNumber( x._value / (y._value * 2) );
}
public static RetardedNumber operator /( RetardedNumber x, RetardedNumber y )
{
return new RetardedNumber( x._value * (2 / y._value) );
}
public double Value
{
get { return _value; }
set { _value = value; }
}
public override string ToString()
{
return _value.ToString();
}
}
}
what about cod?
I think this guy needs your c0d Wossy
http://vbforums.com/showthread.php?t=401348
Thanks, wossname. That's something to put on my CV:
"Helped pioneer an alternative numbering system, called the Retarded Number System™"
lol!