templates used on map container

I've got the following code:

Code:

---

template <typename T> int Histogram<T>::get_occurances(const T& obj)
{
        map<T,int>::iterator find_occur = frequency.find(obj);
       
        if ( find_occur == this->frequency.end() )
        {
            return 0;
        }
       
        return ( find_occur->second );
}

---

The following line always gives me an error saying ';' expected before find_occur.

map<T,int>::iterator find_occur = frequency.find(obj);

If I change the first argument of the map to something other than T, then it works fine, but I need the template type. Is there something I'm doing wrong?

Assuming you have a recent compiler the code should be:

Code:

---

typename map<T,int>::iterator find_occur = frequency.find(obj);

---

The typename indicates to the compiler that iterator is a type and not another kind of class member.

Quote:

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Originally Posted by twanvl

Assuming you have a recent compiler the code should be:

Code:

---

typename map<T,int>::iterator find_occur = frequency.find(obj);

---

The typename indicates to the compiler that iterator is a type and not another kind of class member.

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Thanks twanvl,

I would have never figured this out. I've always been confused as to why you must use the typename keyword like that.