Probability (Binomial distribution (?))
I've been stuck with this exercise for a while now and can't really find the right approach to solving it, here it is:
The average number of phone calls per minute is 1.2, what would the probability of receiving say 2 phone calls in one minute?
I've tried solving this using binomial distribution, but couldn't really find a suitable "n". I've also tried taking the average (1.2) as the expected value E(x) but ended up even worse :sick: ...which lead me to think I'm approaching it completely the way.
Any help is appreciated.
Thanks.
Re: Probability (Binomial distribution (?))
The phenomenon of waiting lines is suitably described by the Poisson distribution. The result is p(k = 2) = 0,2168.
http://img87.imageshack.us/img87/3719/poisson9eh.th.jpg
Rui
Re: Probability (Binomial distribution (?))
thanks for the explanation, I did some research on the Poisson distribution, interesting, interesting lol... :thumb: