<?> Inside a zip file (making changes)

I am receiving a zip file from an outside vendor.
The file name is similar to
abc242.20001110.1252.zip
I am shelling pkzip to unzip this file so before I can
do that I must rename the file as pkunzip does not handle long names. Not a problem.
However when I try to extract it, the file inside the zip file has the same name (abc242.20001110.1252.txt) with a txt extension.
Problem: pkunzip can't handle the long name

Is there some way to change this name (insdie the zip file) and have the file unzipped by PKUNZIP. Winzip is available but I haven't tried it as I don't want any user intervention...I would like this done behind the sceens as the user just starts the program, enters a date, and the app does the rest wihtout any further process by user.

there is a version of pkzip on their website that
works with long filenames

command line version 2.50

Maybe the file format specification of a zip file helps you.

btw, when I tried to reply to this thread, this forum said
'Invalid thread specified'. :( And when I went again to general vb questions, the thread was gone. Then I clicked refresh, and the thread was there and I could reply again.:)

Quote:

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there is a version of pkzip on their website that
works with long filenames

command line version 2.50

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Click here to download PkZip 2.50

Thanks

btw, here's how you can get the long filename out of the zip without listing them with pkzip:
http://forums.vb-world.net/showthrea...threadid=37650

Back to the drawing board. This newer version of pkunzip deals with long names but not on NT.

kedaman, I tried your code but I can't make head nor tail out of it.

[code]
Function FilesInZip() As String()
Dim temp As fileHeader, buffer() As Byte, n As Long, result() As String
Open "C:\windows\desktop\zip_form.zip" For Binary As 1

1> What am I passing to the function?()
2> I assum C:\windows\desk is the file you want to get into
3> I assum you get an 8 digit name in return.

Help!

well, i was just experimenting with something i got from wotsit, btw a great site :) So i guess i can improove it a bit, send file as a string and it will open it.

Code:

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Function FilesInZip(file as string ) As String()
  Open file For Binary As 1

---

Nope i've tested, it returns full names, in a variable length string array.
The thing is that i read a fixed length header, of which i get the name length (in a specific integer). Next i read the filename itself. Strconv just converts the byte array into string. next theres something i'm not too sure about, some version of zips have an extra descriptor which i have to jump over. The whole loop goes until the end of file and skips directory data by checking for the signature in the header. :rolleyes: