how to show a link depending on script variable value

Hi, I'm really new to PHP folks and have this line in a php script and would like to display download links on a page depending on what the variable value of item_name is.

<?=$_POST[item_name]?>

In VB it would be something like this:

VB Code:

link1 = "http://www.mysoftwareco.com/download1.php?"
link2 = "http://www.mysoftwareco.com/download2.php?"
 
if item_name.Value = "Software1" then
'Show link1 on the page else
Print link1
Elseif item_name.value = "Software2" then
'Show link2 on the page else
Print link2
end if

so is it possible to do this in php?

Thanks in advance

Cheers!

Try something like this. If your new to PHP i suggest searching this forum for tutorials as people have posted some good links to help begginers.

PHP Code:

---

<?
$link1 = "http://www.mysoftwareco.com/download1.php?";
$link2 = "http://www.mysoftwareco.com/download2.php?";

if($_POST['item_name'] == "Software1")
{
    print $link1;
}
elseif($_POST['item_name'] == "Software2")
{
    print $link2;
}

?>

---