[RESOLVED] Count

Hi all,
I'm doing a quiz. Every time the user clicks on the question button a count is increased by 1 (count+=1).
What i want to do is when count equals say 1,3,5,7,9 etc something will happen. I want to do this in one IF - THEN statment instead of having IF count = 1 THEN do something,IF count = 3 THEN do something?

so to clarify, you want the if statement to do something if COUNT is odd?

To detect an odd number you would use the Mod operator:

VB Code:

If count Mod 2 = 1 Then
    'count is odd.

No not really, it could be any number.....
if count hits lets say five different numbers do i have to write five IF, THEN statements or can i write one IF, THEN statement to include the five numbers. (if count = 1 2 3 4 5 then
do something
end if

private bool IsOdd(int number)
{
if (number % 2 != 0)
return true;
else return false;
}

true = odd #
false = even #

So you're saying that odd numbers is not the general case? Why give such a specific example if it can be anything? Anyway, if there is a pattern to the number syou want to catch then you'll need to let us know what that pattern is. If there is no patter then you can use a Select Case to catch them all with one line:

VB Code:

Select Case count
            Case 1 To 4, 6, 8, 12 'Matches 1, 2, 3, 4, 6, 8 and 12.
                'Do something here.
        End Select

I do apologize if my thread was misleading :blush:. I did mean random numbers.
Select case will do just fine.
thank you for your help.