Problem passing multiple arguments to php script
Hi all i have problem passing the multiple arguments to a php script . I call a script like beleow:
mp3player.swf?playlist=playlist3.php?Id[]=3&Id[]=7
from :
main code:
Code:
<html>
<head>
<title>JW Flash MP3 Player</title>
</head>
<body>
<object type="application/x-shockwave-flash" width="280" height="280"
data="mp3player.swf?playlist=playlist.php?Id[]=5&Id[]=7">
<param name="movie" value="mp3player.swf?playlist=playlist3.php?Id[]=3&Id[]=7" />
</object>
</body>
</html>
When i use the 1th part only which is in bold the scripts work fine and goes plays all songs from directory:
Code:
1th part
while($i = readdir($fdir)) {
// if a .mp3 string is found, add the file to the array
if (strpos(strtolower($i),".mp3") !== false) {
$playlist[$n] = $i;
$n++;
}
}
But when i remove 1th bold part and use 2th bold part it only plays for me the first song which is the first passed value but not the second passed value. Could any one help me what is wrong here ?Thanks
Code:
2th part:
while($i = readdir($fdir)) {
list($name, $ext) = explode('.', $i, 2);
if(strtolower($ext) == 'mp3' && in_array($name, $_GET['Id'])){
$playlist[$n] = $i;
$n++;
}
}
playlist3.php code with both bold part .When i run i use one of them each time
Code:
<?php
// setting the directory to search for mp3 files
$dir = "mp3/";
// reading the directory and inserting the mp3 files in the playlist array
$n = 0;
$playlist = array();
$fdir = opendir($dir);
1th part
while($i = readdir($fdir)) {
// if a .mp3 string is found, add the file to the array
if (strpos(strtolower($i),".mp3") !== false) {
$playlist[$n] = $i;
$n++;
}
}
2th part:
while($i = readdir($fdir)) {
list($name, $ext) = explode('.', $i, 2);
if(strtolower($ext) == 'mp3' && in_array($name, $_GET['Id'])){
$playlist[$n] = $i;
$n++;
}
}
// close the directory and sort the array
closedir($fdir);
//array_multisort($playlist);
//print_r($playlist);
// echoing the playlist to flash
echo "<player showDisplay=\"yes\" showPlaylist=\"no\" autoStart=\"yes\">\n";
for ($i=0; $i<sizeof($playlist); $i++) {
// for the title it filters the directory and the .mp3 extension out
echo " <song path=\"$dir$playlist[$i]\" title=\"".str_replace(".mp3","",$playlist[$i])."\" />\n";
}
echo "</player>";
?>
Re: Problem passing multiple arguments to php script
I think your problem may be the use of brackets? Are the songs named using numbers, i.e 1,2,0 ? etc.
Try this:
PHP Code:
rewinddir($fdir);
while(($i = readdir($fdir)) !== false) {
list($name, $ext) = explode('.', $i, 2);
if((strtolower($ext) == 'mp3') && in_array($name, $_GET['Id'])){
$playlist[$n] = $i;
$n++;
}
}
The check for !== flase is important when using readdir() a check for equality is not enough. Notice also how I have used rewinddir() before to start searching the directory from the beginning.
Also, if you use PHP 5, then you can edit and save the XML a lot easier by using Simple XML and DOM.
Re: Problem passing multiple arguments to php script
Quote:
Originally Posted by visualAd
I think your problem may be the use of brackets? Are the songs named using numbers, i.e 1,2,0 ? etc.
Try this:
PHP Code:
rewinddir($fdir);
while(($i = readdir($fdir)) !== false) {
list($name, $ext) = explode('.', $i, 2);
if((strtolower($ext) == 'mp3') && in_array($name, $_GET['Id'])){
$playlist[$n] = $i;
$n++;
}
}
The check for !== flase is important when using readdir() a check for equality is not enough. Notice also how I have used rewinddir() before to start searching the directory from the beginning.
Also, if you use PHP 5, then you can edit and save the XML a lot easier by using
Simple XML and
DOM.
Many thanks for u reply. i tried your code but no luck only first value get passed!! could u tell me how i can avoid using brackets and instead use Id=1,Id=2? i be happy if u help me .Thanks
Re: Problem passing multiple arguments to php script
Unfortunatly you cannot do it any other waay (as far a I am aware in PHP). You could have a comma delimetered list and use explode to load it into an array when the script starts.
For now, try replacing the quare brackets with their url encoded equivilents: [ = %5B and ] = %5D
Re: Problem passing multiple arguments to php script
You need to use urlencode as the you have two '?' within the URL which will throw off php.
PHP Code:
<html>
<head>
<title>JW Flash MP3 Player</title>
</head>
<body>
<object type="application/x-shockwave-flash" width="280" height="280"
data="mp3player.swf?playlist=<?= urlencode('playlist3.php?Id[]=3&Id[]=7') ?>">
<param name="movie" value="mp3player.swf?playlist=playlist=<?= urlencode('playlist3.php?Id[]=3&Id[]=7') ?>" />
</object>
</body>
</html>
Re: Problem passing multiple arguments to php script
Quote:
Originally Posted by john tindell
You need to use
urlencode as the you have two '?' within the URL which will throw off php.
PHP Code:
<html>
<head>
<title>JW Flash MP3 Player</title>
</head>
<body>
<object type="application/x-shockwave-flash" width="280" height="280"
data="mp3player.swf?playlist=<?= urlencode('playlist3.php?Id[]=3&Id[]=7') ?>">
<param name="movie" value="mp3player.swf?playlist=playlist=<?= urlencode('playlist3.php?Id[]=3&Id[]=7') ?>" />
</object>
</body>
</html>
Thank u for u reply. I tried your code by putting it inside php file and run it now the first song also does not play!!! Here i the code the out put in browser:
Code:
<html>
<head>
<title>JW Flash MP3 Player</title>
</head>
<body>
<object type="application/x-shockwave-flash" width="280" height="280"
data="mp3player.swf?playlist=playlist3.php%3FId%5B%5D%3D3%26Id%5B%5D%3D7">
<param name="movie" value="mp3player.swf?playlist=playlist=playlist3.php%3FId%5B%5D%3D3%26Id%5B%5D%3D7" />
</object>
</body>
</html>
