Probability quesiton - please help me! argh!

I really appreciate your help! I'm a little stumped/confused. I have three questions - any help is much appreciated.

1. Given that P(A) = 0.75, P(BlA)=0.8 and p(BlA') = 0.6 caclulate P(B) and P(AlB).

2. Two events A and B are such that P(A) = 3/4, P(BlA) = 1/5 and P(B'lA') = 4/7. By use of a tree diagram or otherwise find -

a) P(A and B) B) P(B) c) P(AlB)

3. A batch of forty tickets for an event at a stadium consists of 10 tickets for the north stand, 14 tickest for the east stand and sixteen tickets for the west stand. A ticket is taken from the batch at random and issued to a person, X. Write down the probability that X has a ticket for the north stand.

A second ticket is taken from the batch and issued to Y. Then a third ticket is taken and issued to Z. Calculate the probability that -

a) Both X and Y have tickets for the north stand.

B) X, Y and Z all have the same tickets

c) Two of X, Y and Z have tickets for one stand and the other of X, Y and Z has a ticket for different stand.

I can do all of question 3 apart from c)

Thanks very much for any help!