Adding Two Picture box

The VB attachment regarding for connects two Picturebox by a line connector. In this project there is two button one for adding Picture box and another one for drawing line as connector.I am facing problem to connect the two picturebox by lineconnector button. While Picture box moving the picturebox loose its connections with previous picture box. I want to join the picturebox by the lineconnector. And the pictureboxs always in connected via the line even the picturebox move by mouse move???Anyone have an idea how to slove this problem?????

Can any one help my project?????May be i didnot explain better in my post.I will better expalin if any one have specific question regarding the project..thanks in advance.

most people use .zip so any chance for that? .rar i cant open and many others dont have winrar either.

I upload the its .Zip file again in this post.Anyway thanks for ur information.I am not aware about this info in before.

ill check it when i get back from work and ill see if i can see anything wrong with you code.

ok, the first line you have

VB Code:

Dim i, j, K, m As Integer

you do know that i, j, k would be variant because they are not specified as anything else right?

VB Code:

Private Sub SetLine(X As Single, Y As Single)
    'Stting line Co-ordinate(Start ponit and End Point)
    cx2 = X
    cy2 = Y
    
    m1 = (cx1 + cx1) / 2
    m2 = (cy1 + cy2) / 2
    
    With MyLine.Item(Linecount - 3)
        .X1 = cx1
        .Y1 = cy1
        .X2 = m1
        .Y2 = m2
    End With
    
    With MyLine.Item(Linecount - 2)
        .X1 = m1
        .Y1 = m2
        .X2 = X
        .Y2 = m2
    End With
    
    With MyLine.Item(Linecount - 1)
        .X1 = X
        .Y1 = m2
        .X2 = X
        .Y2 = Y
    End With
End Sub

I am not able to make much sense of the above. youre using variables but many i cant find as having a value? for example: cx1 and cy1.

last of all

VB Code:

Private Sub Command2_Click()
'Activating connector button
blFlag = True
End Sub

youve set a boolean flag to true and youre doing nothing else. command2 is for the lineconnector commandbutton so shouldnt you call the setline sub from there?

meaning something like:

VB Code:

Private Sub Command2_Click()
'Activating connector button
blFlag = True
SetLine 'could say call SetLine, but just saying SetLine does the same thing
End Sub

VB Code:

Dim i, j, K, m As Integer

variant i is used for creating pcturebox array or index...I meam in every click on addpicturebox creat a new picturebox
variant j is used for moving the picturebox on form.

VB Code:

For j = i To 1 Step -1

.
k and m i dont use it at yet.I decleard it just if i may have use it later like to remove the line on using another command button.

VB Code:

Private Sub SetLine(X As Single, Y As Single)

I use the setline function coz when u r going to draw the line in this project in runtime u get there is three step in each line and each of them have three individual index which i declared as linecount.the co-ordinate of this three step is codded as

VB Code:

With MyLine.Item(Linecount - 3)(First step is for drawing a verticle line)
        .X1 = cx1
        .Y1 = cy1
        .X2 = m1
        .Y2 = m2
    End With
    
    With MyLine.Item(Linecount - 2)(2nd step drwaing a horizontal line)
        .X1 = m1
        .Y1 = m2
        .X2 = X
        .Y2 = m2
    End With
    
    With MyLine.Item(Linecount - 1)(third step drawing another last verticle line)
        .X1 = X
        .Y1 = m2
        .X2 = X
        .Y2 = Y
    End With

The value of cx1 and cy1 getting from this line during mouse down period

VB Code:

Private Sub PicArray_MouseDown(Index As Integer, Button As Integer, Shift As Integer, X As Single, Y As Single)
cx1 = PicArray.Item(Index).Left + PicArray.Item(Index).Width / 2
cy1 = PicArray.Item(Index).Top + PicArray.Item(Index).Height

value of m1 and m2 getting from

VB Code:

m1 = (cx1 + cx1) / 2
    m2 = (cy1 + cy2) / 2

value of cx2 and cy2 getting from

VB Code:

cx2 = PicArray.Item(Index).Left + PicArray.Item(Index).Width / 2
 cy2 = PicArray.Item(Index).Top

I set bflag coz i have two parallel works in mouse down period.

VB Code:

Private Sub PicArray_MouseDown(Index As Integer, Button As Integer, Shift As Integer, X As Single, Y As Single)If blFlag = True Then
    FromPicture = Index
    Screen.MousePointer = vbCrosshair
    Line1 = True
......................
...............'Picture box Moving by Mouse Down
NewX = PicArray(Index).Left + X
NewY = PicArray(Index).Top + Y
Dim j As Integer
    For j = i To 1 Step -1
    If (PicArray(Index).Visible = True) And

So when one works is active another should be inactive.I just use bflag true or false only active the line drawing works when linconnector button click and keep the other works like moving picturebox inactive.
U can ask more regarding this,If this above info is not enough.

i want to move the line alongwith picturebox move........but in this project i am not able to do this i.e the line is keep in its positions while moving the picturebox.Simply the line would like to use just as a connector.

We've all been seeing the problem but not correcting it.. the basic fix is pretty easy unless I'm not understanding what the program's supposed to do.

Change this line:

VB Code:

Dim i, j, K, m As Integer

to this:

VB Code:

Dim i As Integer, j As Integer, K As Integer, m As Integer

I update the program according to ur corrections..............In this project there is two button one for adding Picture box and another one for drawing line as connector.i just able to add picturebox and draw line on lineconnector button click. I wish the picturboxs are always in connected via the line appears on lineconnector button click.But now While Picture box moves it loose its connections with previous picture box. I want to join the picturebox by the lineconnector. And the pictureboxs always in connected via the line even the picturebox move by mouse move......................

Recalculate the lines on the event where the picture box is moved.

If this is a single line with single index then its not a very difficult task it.But the main problem I use three index for drwaing a single connections coz the connector line has three steps with three individual index.....one clue i can give you...In PicArray_Mousemove we need to ensure the line co-ordinate.......
Line starting point (cx1,cy1) start from middle of the picturebox on upper side, end point(cx2,cy2) end at top middle portion of the picturebox on dow side.
I edit the code like that

VB Code:

Private Sub PicArray_MouseMove(Index As Integer, Button As Integer, Shift As Integer, X As Single, Y As Single)
    'Picture box moving by Mouse Move
      If Line1 = True Then
        X = PicArray.Item(Index).Left + X
        Y = PicArray.Item(Index).Top + Y
        SetLine X, Y
        
        If FromPicture <> 0 And FromPicture <> Index Then
        cx2 = PicArray.Item(Index).Left + PicArray.Item(Index).Width / 2
            cy2 = PicArray.Item(Index).Top
            SetLine cx2, cy2
            Line1 = False
            FromPicture = 0
            Screen.MousePointer = vbDefault
        Else
            If FromPicture <> 0 And FromPicture <> Index Then
                Unload MyLine.Item(Linecount - 3)
                Unload MyLine.Item(Linecount - 2)
                Unload MyLine.Item(Linecount - 1)
                Line1 = False
            End If
        End If
    End If
    NewX = PicArray(Index).Left + X
    NewY = PicArray(Index).Top + Y
        If DRAGGED_SHAPE <> -1 Then
            PicArray(DRAGGED_SHAPE).Left = NewX - distX
            PicArray(DRAGGED_SHAPE).Top = NewY - distY
          If Linecount >= 3 Then
           cx1 = PicArray.Item(Index).Left + PicArray.Item(Index).Width / 2
           cy1 = PicArray.Item(Index).Top + PicArray.Item(Index).Height
           cx2 = PicArray.Item(Index).Left + PicArray.Item(Index).Width / 2
           cy2 = PicArray.Item(Index).Top
            m1 = (cx1 + cx1) / 2
            m2 = (cy1 + cy2) / 2
           With MyLine.Item(Linecount - 3)
        .X1 = cx1
        .Y1 = cy1
        .X2 = m1
        .Y2 = m2
    End With
    
    With MyLine.Item(Linecount - 2)
        .X1 = m1
        .Y1 = m2
        .X2 = X
        .Y2 = m2
    End With
    
    With MyLine.Item(Linecount - 1)
        .X1 = X
        .Y1 = m2
        .X2 = X
        .Y2 = Y
    End With
        End If
        End If
End Sub

I am facing problem now i cannot fixed the line co-ordinate during picturebox moving period with mouse event.....

VB Code:

Private Sub PicArray_MouseMove(Index As Integer, Button As Integer, Shift As Integer, X As Single, Y As Single)
.........
.........
.........
[COLOR=DarkRed]cx1 = PicArray.Item(Index).Left + PicArray.Item(Index).Width / 2
cy1 = PicArray.Item(Index).Top + PicArray.Item(Index).Height
cx2 = PicArray.Item(Index).Left + PicArray.Item(Index).Width / 2
cy2 = PicArray.Item(Index).Top[/COLOR]

The problem I think in mouse move period the start point of the line (cx1,cy1) and the end ponit of the line (cx2,cy2) get the same pictureindex.But i coudnot fixup the problem.It will be sloved if it is possible to declare start line ponit getting the picture index from where its start and end line point getting the picture index where it would to be end.I higlighted the portion on red color.Can any one give the idea???????