The limit as cats approaches infinity is...

Rep points for the winner.

-1 :bigyello:

Quiz question: would that be a horizontal or vertical asymptote?

Horizontal of course, only wouldn't 0 be the correct answer in that case? Yep. :thumb:

Infinite...do I win now?

Good. Now what is the second antiderivative of 9.8?

This should be easy. It since 9.8 is the acceleration due to gravity.

4.9x²+Cx+C

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Originally Posted by eyeRmonkey

Rep points for the winner.

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Cats will never approach infinity.

Cause God kills too many kittens.

Dogs will rule the earth as they will approach infinity because they are, well, dogs. :D

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Originally Posted by capsulecorpjx

Cats will never approach infinity.

Cause God kills too many kittens.

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And Schroedinger has the rest.

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Originally Posted by timeshifter

4.9x²+Cx+C

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Very good. :)

How long ago did you take calc?


You know what the sad part is? We havn't even learned about integrals yet. I actually read ahead in the book. I'm pathetic, I know. :)

started my junior year in high school.. that's almost two years ago...

twelvty

?? Calc? last time I was in calc was 2 days ago..

Start > Run > Calc.exe
;)

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Originally Posted by wossname

twelvty

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Warning, this is also the same as schfifty five ;)

This thread has really made my day.

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Originally Posted by thegreatone

Warning, this is also the same as schfifty five ;)

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shwam? doo? doo and heif? sheven? shfor-teen-teen?

...

schfifty five?

isn't anti derivitive = integrate then it shoudl only be f(x) = 9.8x + c

second antiderivative... so take the integral of what you have.

Timeshifter is correct. (As always ;))

Me and my friend were teaching ourselves integration today and we couldn't figure out how to do the integral of 2 polynomials divided by each other (we couldnt find it in the book):

2x²+9
5+x+x³

Someone want to walk me through that? hehe.

Damn... i should really read stuff more carefully :blush: , makes me think how badly i must of stuffed up my last exams

Quick tips:
If the top is the derivative of the bottom then its log to the base e of the bottom:
2x+9
x²+9x+3
= ln(x²+9x+3) + c
if the top is of a higher degree than the bottom, then you'll need to do long devision, then integrate it. Also try finding out a way to simplify the equation before integrating.

OMG, stop reminding me of school :eek:

I've been trying very hard to forget it all.

Quote:

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Originally Posted by Andrew G

Quick tips:
If the top is the derivative of the bottom then its log to the base e of the bottom:
2x+9
x²+9x+3
= ln(x²+9x+3) + c
if the top is of a higher degree than the bottom, then you'll need to do long devision, then integrate it. Also try finding out a way to simplify the equation before integrating.

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By long division do you mean synthetic division?

When reading ahead in the book, I saw a bunch of stuff on log and ln, but I didn't get a chance to see when and where you used it. It did mention that you had to use it when the exponenet was -1 though.

No... urgh... hang on I'll dig up my old maths books that I've been meaning to throw out :D


What are you doing in school at this time of the year :confused:

∫(1/x) = ln|x| + c

so it follows that

∫(ax/bx)
= ∫[ax*(1/bx)]

... eh... work it out yourself :D

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And Schroedinger has the rest

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Hiesenberg isn't certain about that, you know.

ASM > Maths

asm == maths

mostly

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Originally Posted by penagate

No... urgh... hang on I'll dig up my old maths books that I've been meaning to throw out :D


What are you doing in school at this time of the year :confused:

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I wish I was out of school this early. Winter break doesn't start for another 2 weeks.

Even if I was out of school, I would still be reading my calc book. I am just nerdy like that... Well, maybe I wouldn't be learning calc during winter break, but thats only because I would be programming. :)

speakin of programmin.. I think i'm gonna start work on another fairly big project... nothing compared to MSP, but still big nonetheless... and i was wondering if anyone wanted to help me in creating the plot, items, locations, blah blah blah behind the game...

Quote:

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Originally Posted by penagate

∫(1/x) = ln|x| + c

so it follows that

∫(ax/bx)
= ∫[ax*(1/bx)]

... eh... work it out yourself :D

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but when you use the power rule thingy:

∫[xⁿ]
= (xⁿ⁺¹)/(n+1)

Then

∫[ax*(1/bx)]
= ∫[ax*(bx)^-1]

That makes n=-1 in this case and n+1 = 0 so that part would go away... right? Thats the part that was confusing me before. Or am I missing something involving log or ln?

Quote:

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Originally Posted by timeshifter

speakin of programmin.. I think i'm gonna start work on another fairly big project... nothing compared to MSP, but still big nonetheless... and i was wondering if anyone wanted to help me in creating the plot, items, locations, blah blah blah behind the game...

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So it will be a game? Aren't you still missing your VB6 DLLs?

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Originally Posted by eyeRmonkey

So it will be a game? Aren't you still missing your VB6 DLLs?

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I've got the runtimes, so I have no problems programming as long as there arent many components or references used... I do have the RichTextBox component, and that's really all I need for what I'm doing.

Okay... sounds good. What are you doing then? A game? Thats what it sounded like.

yeah. Kinda like a Mud game without the multiplayer part.. just a large, text based, single player adventure.. with a rep system to make things interesting...

It's gonna be almost pure code.. hell, the GUI is already done.. just a rich text box, text box, frame, and a few labels.. all the rest is code..

damn this is gonna take a long time..,

Ya know what? I'm just gonna start a thread in the Project Comm area... if you want to help with design (that's all i'm doing right now), then just pop in and check it out. All ideas welcome, most serious ones will likely be used!

Sounds good. I'll check it out.

So back to integration. Does anyone have any insight into my question in post #32?

Can't help with that, but as for the thread title?

The limit as cats approaches infinity is...

42

I demand a strict mathmatical proof of how you came to that conclusion!

:D