After saving, doesnt work

In form 2 there is a textbox1

Button1 is supposed to run the process stated in textbox1

VB Code:

Process.Start(Form2.Textbox1.text)

This code is run and the appliction has no errors until:

Textbox1.text is saved and when form 2 loads again, the saved text is in textbox1 again

VB Code:

Textchanged
SaveSetting("Startitup", "Textboxes", "Textbox1.Text", TextBox1.Text)

Form2 Load

VB Code:

TextBox1.Text = GetSetting("Startitup", "Textboxes", "Textbox1.Text", TextBox1.Text)

After i input this save code my button does not run the process in textbox1.

I get this error message:
InvalidOperationException was Unhandled
Cannot start process because a file name has not been provided.

I think the problem is with the saving.
Coz after the saving code the button doesnt run the process
Anybody can help me?

I strongly recommend against using SaveSetting and GetSetting anyway. They use the registry, which .NET applications are supposed to avoid doing if possible. You should generally be using the config file or your own XML files to store application settings. TextBox.Text is a dynamic property so it is very simple: http://msdn.microsoft.com/library/de...albasicnet.asp
VB.NET 2005 adds the My.Settings namespace to make this even easier, although I haven't checked out all the pros and cons just yet.

What you could do is try using someting like this

VB Code:

Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click
        Dim save As New SaveFileDialog
        save.Filter = "A.n.A Files(*.ana)|*.ana"
        save.FilterIndex = 1
        save.InitialDirectory = "C:\"
        save.RestoreDirectory = True
        If save.ShowDialog() = Windows.Forms.DialogResult.OK Then
            Dim nFileNum As Short
            nFileNum = FreeFile()
            FileOpen(nFileNum, save.FileName, OpenMode.Binary, OpenAccess.ReadWrite)
            Dim ****tosave As String
            Dim ****this As Integer
            Dim ***** As Int32
            For ****this = 1 To 150
                ***** = 0
                FilePut(nFileNum, *****, ****this)
            Next
            ****tosave = TextBox1.Text
            FilePut(nFileNum, ****tosave, 1)
            ****tosave = ComboBox1.Text
            FilePut(nFileNum, ****tosave, 50)
            ****tosave = ComboBox2.Text
            FilePut(nFileNum, ****tosave, 100)
            FileClose(nFileNum)
            MsgBox("Done!", MsgBoxStyle.Exclamation, "")
        End If
    End Sub

and then to open the file

VB Code:

Private Sub Button4_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button4.Click
        Dim open As New OpenFileDialog
        open.Filter = "A.n.A Files(*.ana)|*.ana"
        open.FilterIndex = 1
        open.InitialDirectory = "C:\"
        open.RestoreDirectory = True
        If open.ShowDialog() = Windows.Forms.DialogResult.OK Then
            Dim nFileNum As Short
            nFileNum = FreeFile()
            FileOpen(nFileNum, open.FileName, OpenMode.Binary, OpenAccess.ReadWrite)
            Dim ****tosave As String
            ****tosave = Space(50)
            FileGet(nFileNum, ****tosave, 1)
            TextBox1.Text = ****tosave
            FileGet(nFileNum, ****tosave, 50)
            ComboBox1.Text = ****tosave
            FileGet(nFileNum, ****tosave, 100)
            ComboBox2.Text = ****tosave
 
 
        End If
    End Sub