[Resolved] Arrays + Pointers in C

I'm trying to write some code that takes input lines and then outputs the last N lines. But all my code is doing is outputting the last line N times. Here's the code:

Code:

---

#include <stdio.h>

int N = 4;
const int MAX_LENGTH = 50;

int main(int argc, char *argv[]) {

        char **lines;
        char *currLine = (char *) calloc(MAX_LENGTH, sizeof (char));

        int start = 0;
        int current = 0;
        int i = 0;

        if (argc > 0 && isdigit(argv[1])) {
                N = argv[1] - '0';

                printf("%d\n", N);
        }

        lines = (char **) calloc (N, sizeof (char *));
        for (i = 0; i < N; i++)
                lines[i] = calloc(MAX_LENGTH, sizeof (char));


        fgets (currLine, MAX_LENGTH, stdin);
        while (! feof (stdin)) {
                *(currLine + strlen(currLine) - 1) = 0;

                if (current == N) {
                        current = 0;
                        start = 1;
                } else if (start != 0) {
                        if (start == N - 1) {
                                start = 0;
                        } else {
                                start++;
                        }
                }

                *(lines + MAX_LENGTH * current) = currLine;

                printf("%s\n", *(lines + MAX_LENGTH * current));

                current++;

        fgets (currLine, MAX_LENGTH, stdin);
        }

        // output lines:
        for (i = start; i < N; i++) {
                printf("f[%d]: %s\n", i, *(lines + MAX_LENGTH * i));
        }

        if (start != 0) {
                for (i = 0; i < start; i++) {
                        printf("f[%d]: %s\n", i, *(lines + MAX_LENGTH * i));
                }
        }

        free(lines);
        free(currLine);

        return 0;
}

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So if the input is:
Line #1
Line #2
Line #3
Line #4

and N = 2, then the output should be:
Line #3
Line #4

What am I screwing up?

You need to use strcpy to copy the lines to their buffers.

Ah, thanks CB.