[Resolved] DateDiff problem

Hello all. I found the following code which will display the number of days between two dates. The problem is if I take out the "SEP" and replace it with say 9 or 09 it doesn't work.
How would I rewrite this so that I can use all numeric values.
All the dates in my database use yyyy-mm-dd format if that helps.

Code:

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$today=date("d-m-Y");
$date1=strtotime( "1-SEP-2005");

$date2=strtotime($today);

        echo "Difference: ".(($date2-$date1)/86400);

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Many thanks.

Got it.

Code:

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function datediff($start_date, $end_date) {
        list($start_date_month, $start_date_day, $start_date_year) = split('[/.-]', $start_date);
                if (!$end_date) {
                        $end_date_year = date("Y");
                        $end_date_month = date("m");
                        $end_date_day = date("d");
                } else {
                        list($end_date_month, $end_date_day, $end_date_year) = split('[/.-]', $end_date);
                }
                        $start_date = mktime(0,0,0,$start_date_month, $start_date_day, $start_date_year);
                        $end_date = mktime(0,0,0,$end_date_month, $end_date_day, $end_date_year);
                        $difference = $end_date-$start_date;
                                return floor($difference/60/60/24);
}

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