[RESOLVED] Checking Ascii Values

I have a textbox on my form with code in the "keypress" event. In this code it says something like

VB Code:

If KeyAscii = 13 Then

Well, how do I get the actual value that is stored in KeyAscii 13. I want to check each keypress to make sure the user typed in a numeric value.

Something like

VB Code:

If IsNumeric(KeyAscii.Value) Then

You can return the character of an ascii using CHR$(13) but it won't return a character, as it is the ENDLINE CR sequence.

I usually place a breakpoint in my code and check what was pressed.

0 is chr$(48) and 9 is chr$(57)

This should help.

VB Code:

Private Sub Text1_KeyPress(KeyAscii As Integer)
If (KeyAscii < 48 Or KeyAscii > 57) And KeyAscii <> 46 And KeyAscii <> 13 Then
    MsgBox "Only numbers are allowed for this entry"
    KeyAscii = 0
    Exit Sub
End If
End Sub
 
'also, in the change event put this code
'to prevent pasting in non numeric text
Private Sub Text1_Change()
If Not IsNumeric(Text1.Text) Then
   MsgBox "Only Numbers Are Allowed"
   Text1.Text = vbNullString
   Exit Sub
End If
End Sub

I see Hack posted, but I was talking about this:

VB Code:

Option Explicit
 
Private Sub Text1_KeyPress(KeyAscii As Integer)
  MsgBox KeyAscii & "  " & Chr$(KeyAscii)
End Sub

Quote:

---

Originally Posted by The_Grudge

I have a textbox on my form with code in the "keypress" event. In this code it says something like

VB Code:

If KeyAscii = 13 Then

Well, how do I get the actual value that is stored in KeyAscii 13. I want to check each keypress to make sure the user typed in a numeric value.

Something like

VB Code:

If IsNumeric(KeyAscii.Value) Then

---

VB Code:

If IsNumeric(Chr(KeyAscii)) Then

I think martinliss or Joacim wrote this originally. It only allows numbers to be entered into the text box.

VB Code:

Option Explicit
 
Private Declare Function GetWindowLong Lib "user32" Alias "GetWindowLongA" (ByVal hwnd As Long, ByVal nIndex As Long) As Long
Private Declare Function SetWindowLong Lib "user32" Alias "SetWindowLongA" (ByVal hwnd As Long, ByVal nIndex As Long, ByVal dwNewLong As Long) As Long
Private Const GWL_STYLE = (-16)
Private Const ES_NUMBER As Long = &H2000& 'or 8192 in decimal form
 
Private Sub Form_Load()
    Dim style As Long
    Text1.Text = ""
    style = GetWindowLong(Text1.hwnd, GWL_STYLE)
    SetWindowLong Text1.hwnd, GWL_STYLE, style Or ES_NUMBER
End Sub

Thanks Pradeep...that's exactly what I was after.
Usually Hack helps me out of my jams, good to see a new face. LOL :p