Quick Array Question

Is there a way to copy the contents of one array to another without using a loop?

eg. MyArr1() = MyArr2()

i don't think there is. :( im not sure though

but perhaps a variant variable (holds an array aw well) is good ;)

like

VB Code:

Dim myArr(4) As String
Dim myVar As Variant
 
 
'initialize myArr or whatever
 
myVar = myArr
 
'try this one if ok :D
Msgbox CStr(UBound(myVar))

Try this:

VB Code:

Option Explicit
 
Private Sub Form_Load()
  Dim t() As Integer, y() As Integer
  Dim x As Integer, str$
  ReDim t(4) As Integer
  For x = 0 To 3
    t(x) = x
  Next x
  y() = t()
  For x = 0 To 3
    str = str & y(x)
  Next x
  MsgBox str
End Sub

Without a loop...

VB Code:

Option Explicit
 
Private Declare Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" (Destination As Any, Source As Any, ByVal Length As Long)
 
Private Sub Form_Load()
    Dim Arr1(100) As Long
    Dim Arr2() As Long
        ReDim Arr2(UBound(Arr1))
    CopyMemory Arr2(0), Arr1(0), Len(Arr1(0)) * (UBound(Arr1) + 1)
End Sub

via CVMicheal

Mine copies the array without a loop. The loops just load and display data.

Thanks All. Got it working the way I want :D

Darn, the VBForums sever was down when I had this code to post:

VB Code:

Option Explicit
 
Private Declare Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" (Destination As Any, Source As Any, ByVal Length As Long)
 
Private Sub Copy_Array_Long(Destination() As Long, Source() As Long, Length As Long)
    
    CopyMemory Destination(0), Source(0), Length
 
End Sub
 
Private Sub Form_Activate()
 
    Dim A(3) As Long, B(3) As Long
    
    A(0) = 10: A(1) = 20: A(2) = 30
    
    Copy_Array_Long B(), A(), Len(A(0)) * UBound(A)
    
    Print B(0), B(1), B(2)
 
End Sub

Slightly more versatile version of Jake's function

VB Code:

Private Sub CopyLongArray( _
    ByRef psaDestination() As Long, _
    ByRef psaSource() As Long _
)
    CopyMemory psaDestination(LBound(psaSource)), _
               psaSource(UBound(psaSource)), _
               (UBound(psaSource) - LBound(psaSource)) * LenB(psaSource(LBound(psaSource)))
End Sub

I'm using the code submitted by |2eM!x but my question is can I use that code for a 2D Array?

eg MyArr(6,10)

Offhand I don't know how 2D arrays are stored in memory so I couldn't help you with CopyMemory there.

If you declare the arrays as dynamic and subsequently ReDim the source array to the dimensions you want then you can just equate it with the destination array.

e.g.

VB Code:

Dim lArrSrc() As Long
Dim lArrDest() As Long
 
ReDim lArrSrc(6,10)
 
' later
lArrDest = lArrSrc

It only works with dynamic arrays.

Thanks penagate...that's what I was after.

No worries :)