Passing Parameters Into A Form [RESOLVED]

Hi guys,

I've been looking for a way to pass parameters into a form and then use that parameter in the subform once it's been passed. The situation is this - I have a few tables in the current database who's contents I'd like to display. I also have a main form with a command button. The idea is, once the button is clicked, a subform is opened that populates its text and list boxes with information from a particular table, depending on what value was passed in as a parameter (ie: DoComd.OpenForm <subformname>, OpenArgs:="First_Table" will open First_Table, DoCmd.OpenForm <subformname>, OpenArgs:="Second_Table" will open Second_Table etc. etc....)

My question is pretty general - how is this done?

The DoComd... OpenArgs example is something I found earlier but I've no idea how to get the subform to act based on the parameter that was passed into it.

Hope you can help,

Thanks

On load of the form you would need to check the me.OpenArgs.
Add this to an sql statement for the form and set the recordseource (I think) property to the new sql statement. Then it may require a me.refresh/me.requery to get the requested data.

Worth a try to see if it works. Post up if it does/doesn't work.

Thanks. Here's the latest -

I've passed a string parameter into the form, which I'm calling frmEdit. I have a button in frmEdit called CmdEnter. As this button's event procedure, I've instructed it to check Me.OpenArgs and display whatever the arguments are in a textbox, like so -

Dim str As String
str = "Display " & Me.OpenArgs
txtDisp.Text = Me.OpenArgs

It's not displaying the arguments at the moment. Am I on the right track here?

Show your exact DoCmd.OpenForm command

Try a messagebox in the open event of the new form ...

Code:

---

MsgBox Me.OpenArgs

---

Hey! Your question was the solution to my problem! I was trying to set a Label in a Report, and it works if I pass an "OpenArgs" to the Report and use it to set the Label.Caption in the Report Open Event, but it does not work (on the 1st page) if I try to set the Label.Caption in the control Button click event!

Thanks, good luck, and good programming!

Here is my code that works ...

Code:

---

'>>>    In Control Form Module
Private Sub Command0_Click()
    Dim aWhere As String
    Dim aStrArg As String
   
    'Select a WHERE statement (from Global List) based on the Radio Box Group
    aWhere = aDept(Me.Dpt_Chain.Value)
    'Pass a String Argument to the Report to install in the Lable
    aStrArg = "TEST 22"
    'Open the Report and pass it a string ...
    DoCmd.OpenReport "Price_1", acViewPreview, , aWhere, acWindowNormal, aStrArg
 
End Sub

'>>>    In Report Code
Private Sub Report_Open(Cancel As Integer)
 
  If Not IsNull(Me.OpenArgs) Then
      Me.Controls("Dpt_Label").Caption = Me.OpenArgs
  End If
 
End Sub

---

I've made some of the changes suggested here and I've studies the info available on the MSDN library. My code now reads like so -

VB Code:

'This is the code in the form that will open the second (or sub) form
 
Private Sub OpenEditForm()
    
    Dim strRep As String
    strRep = "Test Argument Passing"
    Dim db As Database
    Dim rs As Recordset
    Dim sqlStr As String
    Set db = CurrentDb()
    DoCmd.SetWarnings (False)
    DoCmd.OpenForm "frmEditMon", , , , , , strRep
    
End Sub
 
'This is the code in the subform
 
'CmdMonEnt is a command button
Private Sub CmdMonEnt_Click()
    Dim str As String
    str = "Display : " & Me.OpenArgs
    'txtDisp is a textbox
    txtDisp.Text = Me.OpenArgs
    If Not IsNull(Me.OpenArgs) Then
        MsgBox Me.OpenArgs
    End If
End Sub

Everything compiles ok and there are no errors but the subform isn't displaying the argument string that I'm passing in to it. Any ideas?

DoCmd.OpenForm "frmEditMon", , , , , , strRep

IGNORE THIS ... I Confused OpenForm with OpenReport
I think you have 1 too many commas ... as I recall OpenArgs is the SIXTH parameter.

OOPS! OpenForm seems to have 1 more parameter than OpeReport ...

expression.OpenReport(ReportName, View, FilterName, WhereCondition, WindowMode, OpenArgs)

expression.OpenForm(FormName, View, FilterName, WhereCondition, DataMode, WindowMode, OpenArgs)

Put a message box in the OPEN Event for the subform ... I'll bet you'll find it there. Pass the parameter to a Public (Global) variable in the Open Event code and it will be available to the rest of the code for the form.

Thanks - that pretty much clinched it.

This is the line of code that opens the form

DoCmd.OpenForm "<form name>", , , , , , strArgument

And this is the code in the Subform that gets the parameter

Private Sub Form_Load()
strArg = Me.OpenArgs
MsgBox "Parameter : " & strArg
End Sub

Thanks for all the help.