[RESOLVED] It works here... but not over there?

I bet at least some of you know the following code string well:

VB Code:

RndLabel.Text = (Int(Rnd() * 10))

Well, this works in one of my programs doing the exact same thing - setting a label's code to a random number between zero and nine. However, in a different program, the following:

VB Code:

Rnd() * 10

Is underlined. The mouseover 'explanation' tells me "Operator '*' is not defined for types 'System.Windows.Forms.Label' and 'Integer'".

Direct excerpt from my program:

VB Code:

If Roomnmberrnd.Text = "102" Then
            Rnd.Text = (Int([U]Rnd() * 20[/U]))
        End If

Why does it tell me this? :(

Edit: In my program, the 'Rnd.Text' does not have 'Rnd' underlined because that is the name of the label I'm working with (yes, Rnd).

option strict on

VB Code:

Me.TextBox3.Text = (Rnd() * 10).ToString

Quote:

---

Originally Posted by Asgorath

option strict on

VB Code:

Me.TextBox3.Text = (Rnd() * 10).ToString

---

Ok, so suppose this is what I want to do...

VB Code:

If Roomnmberrnd.Text = "102" Then
Me.RndLabel.Text = (Rnd() * 20).ToString
If RndLabel.Text = 1 Then
'Blah, Blah, Blah, etc...
End If
End If

Plus, I just added that same string into my code and it gives me the same problem...

This is what it looked like when it worked:

VB Code:

'After a button was clicked, this was the action:
Encounternumber.Text = (Int(Rnd() * 10))
 
'Separate button...
 
        If PartyLevelInput.Text = "1" Then
            If Encounternumber.Text = "1" Then
                'Blah blah, very long stuff
            End If
        End If

That worked - it generated completely random bits of information based on the number generated by (Int(Rnd() * 10) from the first button. However, now that I'm doing it in a different program...

- WHOA -

I just changed the name of the label (from "rnd" to "rndlbl") and it works?!

OK, keep that in mind. Thanks asgorath. :)

The code now reads, lol:

VB Code:

Rndlbl.Text = (Int(Rnd() * 20).ToString)

That generates an integer between 0 and 19, which is what I want. Thanks again, i'll use that in the future

If you have a control or some other variable called "Rnd" then you need to qualify the method named "Rnd" so the compiler doesn't confuse the two, i.e. VBMath.Rnd() or Microsoft.VisualBasic.VBMath.Rnd(). Better you don't call anything else "Rnd" I think. It's not a very descriptive name anyway. You could also use the System.Random class instead.

Edit:
Just missed out. :cry: