[RegEx] finding a word BEFORE a (

How do I do that...like if I have this:

Code:

---

#Hello mother
def main():
    if len(sys.argv) < 1:
        usage() #Yeah thats your mother all right
    else:
        kek_number_list = tidy_up_file(sys.argv[1])
       
        if kek_number_list != -1:
            download_pdf(kek_number_list)

---

It should match "main", "len", "usage", "tidy_up_file", and "download_pdf", but NOT the ( after it.


I tried this:
\s[\d\w^\S]*\(

and it matches the word in front AND the ( but I don't want the(...:(

This is why I love forums you always find something interesting that expands your knowlodge
RegEx:
\b\w+(?=\()

I think this will work

(?=) is a look ahead assertion matches whats within the (?=) but does not return it.

Edit
knowlodge???
Now all I need is a typing/spelling forum :rolleyes:

Wooohooo...yeah you solved it....I am not at that chapter yet...so you saved me a whole lot of reading there...since a function name can hold numbers or underscores too I had to do this:


\b[\w\d_]*(?=\()

and then it will totaly work...:) Thanks a bunch.