Using vbKeyLButton

Hello all...
I have a multiline text box, where i donot want the user to be able to set the cursor position anywhere using the left mouse click..above the current line. I have tried using text box keydown and keypress, also Text1_MouseDown and check like this:

If KeyCode = vbKeyLButton Then
KeyCode = 0
End If

but still nothing seems to work..can anuybody help me...
thanls

in mousedown procedure...

if button = vbleftbutton then 'do stuff

This will not allow the text cursor to be moved using the mouse.

VB Code:

Private Declare Function ReleaseCapture _
 Lib "user32.dll" () As Long
 
Private nLastSel As Long
 
Private Sub Text1_Change()
    nLastSel = Text1.SelStart
End Sub
 
Private Sub Text1_GotFocus()
    nLastSel = Text1.SelStart
End Sub
 
Private Sub Text1_KeyUp(KeyCode As Integer, Shift As Integer)
    Select Case KeyCode
        Case vbKeyDown, vbKeyUp, vbKeyLeft, vbKeyRight, vbKeyHome, vbKeyEnd
            MsgBox "h"
            nLastSel = Text1.SelStart
    End Select
End Sub
 
Private Sub Text1_MouseDown(Button As Integer, Shift As Integer, X As Single, Y As Single)
    If Button = vbLeftButton Then
        ReleaseCapture
    End If
End Sub

EDIT: Forgot about the arrow keys. Fixed that!

hello joacim,

iam still able to move the cursor using the left mouse button using the code that u wrote..releasecapture api is probably not doing anything...do uahve any suggestions..thanks

Sorry, I forgot the most important part, to reset the text caret. LOL, that whats happens when you write the code directly into the post instead of testing it first. Change the MouseDown code to this:

VB Code:

Private Sub Text1_MouseDown(Button As Integer, Shift As Integer, X As Single, Y As Single)
    If Button = vbLeftButton Then
        ReleaseCapture
[b]        Text1.SelStart = nLastSel [/b]
    End If
End Sub

Quote:

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Originally Posted by Apollyon255

is there anybody here know what is the ascii keyboard value of Function Keys such as F1 tru F12???... i try it to kypress event but it doesn't return any value..

---

First of all, it's considered very unpolite to hog someone elses thread and ask a new question. You should start a new thread instead :).

However, the function keys doesn't have any Ascii values. But you can still trap them using the keyboard scan code. This is done in VB using the KeyDown event instead of the KeyPress event.

VB Code:

Private Sub Form_KeyDown(KeyCode As Integer, Shift As Integer)
    If KeyCode = vbKeyF1 Then
        MsgBox "F1 was pressed"
    End If
End Sub

The named constants for the function keys are vbKeyF1 to vbKeyF12. If you want to try out this code make sure you set the KeyPreview property of the Form to True.

thanks so much joacim, it worked.... :wave: