Using VB to find how many times 2 words appear in the same sentence together?

Hello,


I have this program where the user finds plays the game to find combinations - now what I need the computer to do is have the answers so that when the user clicks on a combination the computer will know whether or not it is a combination?

Now what I mean by combination is:
Example:

I have a whole database of words/sentences.
All I need the computer to do is tell me how many times each word appear with the other word in the same line of text (.txt file)

So lets say I have a sentence like this:
Jake and Alexa went to the movies.
Sam and Alexa are siblings to Jake
---------------------------------------
So "Alexa and Jake" appeared in the same sentence 2 times
Except I need it to get all the other words also and tell me how many times they appear together in 2 word combinations.
Can this even be done?

Thank you for any suggestions info or code! :thumb:
Stilekid007 :wave:

Do you mean in the same line or in the same sentence?

Same Line.
It will be in a .txt file and each line so it will be like this:
Line1. Text here:
Line2. Text here:
Line3. Text here:

So a period won't mark the end of a sentence but rather the end of the line.

The .txt file is loaded into a text box (For your info)
Thank you so much!
Stilekid007

Warning: I am not a programmer, and you need to check this. However- I'd try this. I am assuming the two words are in text boxes called NameOne and NameTwo on the same form

VB Code:

Dim TheList as variant, theCount as long
thelist = split(me.text1,chr(13))
for r = 1 to ubound(thelist,2)
if instr(1,thelist(r),me.NameOne) > 0 and instr(1,thelist(r),me.NameTwo) > 0 then thecount=thecount + 1
next
msgbox "A total of " & thecount & " instances of " & me.nameone & " and " & nametwo & " were found

Are you comparing two lines or just one?

plus, what is the user clicking when you say "when the user clicks on a combination".

casey.

I am comparing a whole bunch of lines - like 50 lines of words.

And I want it to tell me how many times in those 50 lines, 2 words appear in the same line.

So lets say Jake and Alexa appear together in 8 different lines of the 50 lines.

Then it would say:
Jake, Alexa 8

Or something like that.

Right now the user would just click a command button and it will search the textbox.

Thanks everyone!
Stilekid007

Here we go I haven't tested it so save your work before you run it :D

Code:

---

Private Declare Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" _
    (ByRef pDest As Any, _
    ByRef pSrc As Any, _
    ByVal ByteLen As Long)

Private Function CountWords(ByVal lpFirstLine As Long, _
                            ByVal plngLinesUBound As Long, _
                            ParamArray strWords()) _
                          As Long
' IN: lpFirstLine:      Long pointer to the first element of an array
'                      containing the lines to search
' IN: plngLinesUBound:  Upper bound of the array containing the lines
' IN: strWords():      String array of words to search for

    Dim Offset          As Long
    Dim strTemp        As String
    Dim strSentence    As String
    Dim astrWords()    As String
    Dim lngWordsPresent As Long
    Dim i              As Long
    Dim j              As Long

    ReDim alngWordCount(UBound(strWords)) As Long

    ' For each sentence
    For Offset = 0 To (plngLinesUBound * 4) Step 4
        CopyMemory ByVal strTemp, _
                  (lpFirstLine + Offset), _
                  4
        strSentence = strTemp

        astrWords = Split(Trim$(strTemp), " ")

        ' For each word in the sentence
        For i = 0 To UBound(astrWords)

            ' For each word to search for
            For j = 0 To UBound(alngWordCount)
                If (astrWords(i) = strWords(j)) Then _
                    alngWordCount(j) = alngWordCount(j) + 1
            Next j
        Next i

        For i = 0 To UBound(alngWordCount)
            If (alngWordCount(i) > 0) Then _
                lngWordsPresent = lngWordsPresent + 1
        Next i
       
        If (lngWordsPresent = UBound(alngWordCount)) Then _
            CountWords = CountWords + 1
    Next Offset
   
    strTemp = "Zeroed"
End Function

---

Call like this:

Code:

---

Dim astrSentences()    As String
' Populate astrSentences
' and then call the function like this
MsgBox CountWords(VarPtr(astrSentences(0)), UBound(astrSentences), "Jake", "Alexa")

---

Hope it works :eek:

Hello Penagate!

Thank you for getting that code for me.

I get a subscript out of range error with this line of code...

Code:

---

MsgBox CountWords(VarPtr(astrSentences(0)), UBound(astrSentences), "Jake", "Alexa")

---

Also is this only going to search for Jake and Alexa?
Thank you for all your help!
Stilekid007

Thank goodness thats where its crashing not later otherwise it will probably GPF :lol:

Have you dimension the array astrSentences? You have to populate it first.

A sample array would be

VB Code:

Dim astrSentences(3) As String
astrSentences(0) = "Jake and Alexa sat on a bench."
astrSentences(1) = "Jake was very bored."
astrSentences(2) = "Alexa was wearing Jake's thermal underwear."
astrSentences(3) = "Useless sentence without the words J*** and A****."
 
MsgBox CountWords(VarPtr(astrSentences(0)), UBound(astrSentences), "Jake", "Alexa")

To search for other words, just list them after the 2nd parameter, e.g.

VB Code:

MsgBox CountWords(VarPtr(astrSentences(0)), UBound(astrSentences), "Hippo", "Rhinocerous")
 
MsgBox CountWords(VarPtr(astrSentences(0)), UBound(astrSentences), "Badger", "Frog", "Bunny", "Toadstool")

:)

hi penagate,

is there much advanage to your method in speed or other to

VB Code:

For i = 0 To UBound(astrSentences)
If InStr(astrSentences(i), " Jake ") And InStr(astrSentences(i), " Alexia ") Then cnt = cnt + 1
Next
MsgBox "no of occurances = " & cnt

pete

D'oh I completely forgot about InStr :blush:
I bet my method doesn't work anyway, I think the string copying is a bit dodgy.

The thing about my code is I wrapped it in a function and to save passing the whole array (Stilekid said he had 50 or so sentences) I made it so only a pointer to the start of the array is passed and so thats why I had to use Copymemory. And hence the other complications. Also, it accepts a variable number of words to search for, so an extra loop is needed.

Anyway here's the function again using Instr:

Code:

---

Private Function CountWords(ByVal lpFirstLine As Long, _
                            ByVal plngLinesUBound As Long, _
                            ParamArray strWords()) _
                          As Long
' IN: lpFirstLine:      Long pointer to the first element of an array
'                      containing the lines to search
' IN: plngLinesUBound:  Upper bound of the array containing the lines
' IN: strWords():      String array of words to search for

    Dim Offset          As Long
    Dim strTemp        As String
    Dim strSentence    As String
    Dim astrWords()    As String
    Dim lngWordsPresent As Long
    Dim i              As Long

    ReDim alngWordCount(UBound(strWords)) As Long

    ' For each sentence
    For Offset = 0 To (plngLinesUBound * 4) Step 4
        CopyMemory ByVal strTemp, _
                  (lpFirstLine + Offset), _
                  4
        strSentence = strTemp

        astrWords = Split(Trim$(strTemp), " ")

        ' For each word to search for
        For i = 0 To UBound(strWords)
            If (InStr(1, strSentence, astrWords(i))) Then _
                lngWordsPresent = lngWordsPresent + 1
        Next i
       
        If (lngWordsPresent = UBound(alngWordCount)) Then _
            CountWords = CountWords + 1
       
        lngWordsPresent = 0
    Next Offset
   
    strTemp = "Zeroed"
End Function

---

Quote:

---

Originally Posted by anguswalker

Warning: I am not a programmer, and you need to check this. However- I'd try this. I am assuming the two words are in text boxes called NameOne and NameTwo on the same form

VB Code:

Dim TheList as variant, theCount as long
thelist = split(me.text1,chr(13))
for r = 1 to ubound(thelist,2)
if instr(1,thelist(r),me.NameOne) > 0 and instr(1,thelist(r),me.NameTwo) > 0 then thecount=thecount + 1
next
msgbox "A total of " & thecount & " instances of " & me.nameone & " and " & me.nametwo & " were found

---

This used instr(). Also shows how to use split to get the contents of the textbox into an array. Is it OK do you think?

Quote:

---

Originally Posted by anguswalker
Warning: I am not a programmer, and you need to check this. However- I'd try this. I am assuming the two words are in text boxes called NameOne and NameTwo on the same form.

[Highlight=VB]Dim TheList as variant, theCount as long
thelist = split(me.text1,chr(13))
for r = 1 to ubound(thelist,2)
if instr(1,thelist(r),me.NameOne) > 0 and instr(1,thelist(r),me.NameTwo) > 0 then thecount=thecount + 1
next
msgbox "A total of " & thecount & " instances of " & me.nameone & " and " & me.nametwo & " were found [Highlight=VB]

---

I couldn't get this to work. I am not to good at programing in VB yet.

Penagate, With your code my VB program always crashes. And I get an error saying "The memory could not be written."

That is when I click the command button to output the number of words.

I am sorry that I can't fix this myself, but like I said I am not very good yet with VB ;)
I appreciate all your help!
Stilekid007

Quote:

---

Originally Posted by stilekid007

I couldn't get this to work. I am not to good at programing in VB yet.

Penagate, With your code my VB program always crashes. And I get an error saying "The memory could not be written."

That is when I click the command button to output the number of words.

I am sorry that I can't fix this myself, but like I said I am not very good yet with VB ;)
I appreciate all your help!
Stilekid007

---

Hahaha I was afraid of that :lol: Sucks not being able to test it... wait... *flash of inspiration* I can use VBA...

OK I stopped the crash but now I'm getting zero for some resaon... I'll try and fix it for ya.

Thank you so much man! I really appreciate your help buddy!

I don't understand, can't you use the code I posted for you yesterday in this thread?

Here ya go mate

VB Code:

Option Explicit
 
Private Declare Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" _
    (ByRef pDest As Any, _
     ByRef pSrc As Any, _
     ByVal ByteLen As Long)
'
 
Private Function CountWords(ByVal lpFirstLine As Long, _
                            ByVal plngLinesUBound As Long, _
                            ParamArray strWords()) _
                           As Long
' IN: lpFirstLine:      Long pointer to the first element of an array
'                       containing the lines to search
' IN: plngLinesUBound:  Upper bound of the array containing the lines
' IN: strWords():       String array of words to search for
 
    Dim Offset          As Long
    Dim strSentence     As String
    Dim lngWordsPresent As Long
    Dim i               As Long
 
    ReDim alngWordCount(UBound(strWords)) As Long
 
    ' For each sentence
    For Offset = 0 To (plngLinesUBound * 4) Step 4
        strSentence = Space(255)
 
        CopyMemory ByVal VarPtr(strSentence), _
                   ByVal (lpFirstLine + Offset), _
                   4
 
        strSentence = Trim$(strSentence)
 
        ' For each word to search for
        For i = 0 To UBound(strWords)
            If (InStr(1, strSentence, strWords(i))) Then _
                lngWordsPresent = lngWordsPresent + 1
        Next i
 
        If (lngWordsPresent = (UBound(alngWordCount) + 1)) Then _
            CountWords = CountWords + 1
 
        lngWordsPresent = 0
    Next Offset
End Function
 
Public Sub Tester()
    Dim astrSentences(3) As String
    astrSentences(0) = "Jake and Alexa sat on a bench."
    astrSentences(1) = "Jake was very bored."
    astrSentences(2) = "Alexa was wearing Jake's thermal underwear."
    astrSentences(3) = "Useless sentence without the words J*** and A****."
 
    MsgBox CountWords(VarPtr(astrSentences(0)), UBound(astrSentences), "Jake", "Alexa")
End Sub

:)

in your first post you put the sentance
"Jake and Alexa went to the movies. Sam and Alexa are siblings to Jake"

if you look, there is 4 sets of 2 word combinations. (Jake, and, Alexa, to). did all these need finding. Using InStr() could be a problem aswell because you could find words which are inside other words and you would also need to check for any punctuation at the end of words.

casey.

You could use the classes I posted in your other thread yesterday to check the number of occurance for a particular word in this manner.

VB Code:

Dim oWordCount As CWords
Set oWordCount = New CWords
oWordCount.CountWords "Jake and Alexa went to the movies. Sam and Alexa are siblings to Jake"
MsgBox oWordCount("Jake").Count

Quote:

---

Joacim Andersson

VB Code:

Dim oWordCount As CWords
Set oWordCount = New CWords
oWordCount.CountWords "Jake and Alexa went to the movies. Sam and Alexa are siblings to Jake"
MsgBox oWordCount("Jake").Count

---

Hello ya'll!

First off Joacim, for this part of the program it is not just detecting how many times Jake appears in the line but rather, how many times the combination of Jake and Alexa appear in the same line.

Quote:

---

in your first post you put the sentance
"Jake and Alexa went to the movies. Sam and Alexa are siblings to Jake"

if you look, there is 4 sets of 2 word combinations. (Jake, and, Alexa, to). did all these need finding. Using InStr() could be a problem aswell because you could find words which are inside other words and you would also need to check for any punctuation at the end of words.

casey.

---

Yes there are more combinations then just Jake and Alexa, but I have to put this code in manually for each word combos I want to find

Code:

---

  MsgBox CountWords(VarPtr(astrSentences(0)), UBound(astrSentences), "NewWord1", "NewWord2")

---

I was hoping the code would just find all the combo's of words rather then just the ones I input, but oh well.

It will just take me alot longer to do it. So if there is a way to get it to just detect all the combo's rather then just Jake and Alexa (or other inputed words) then please post!

Penagate,

I really appreciate all your time in coding that. It works nicley for finding Jake and Alexa or any other 2 word combos. SO thank you sooo much!

If anyone has got more code with more features I will rate you haha!

I will also rate you Penagate! Its all worth it! :thumb:
Thank you all!
Stilekid007 :wave:

I don't understand what you're looking for. How do you define what a combination is? As I showed you yesterday the classes count each appearance of each and every word what more do you want?

He wants to count the occurrence of each line that has two words in common, I think.

Yes, thats correct diglienna,

Here is 2 Lines:

"Jake is going to town with Alexa." <-Jake and Alexa both appear on this line there for the count would be 1 occurance of Jake and Alexa on one line.

Jake is also going with Sam. <- ALEXA does not appear in this sentence therefore I would not want that occurance of Jake to be counted.

Stilekid007

Is Jake and Alex different from Alex and Jake?

No sir.

Quote:

---

Originally Posted by stilekid007

"Jake is going to town with Alexa." <-Jake and Alexa both appear on this line there for the count would be 1 occurance of Jake and Alexa on one line.

Jake is also going with Sam. <- ALEXA does not appear in this sentence therefore I would not want that occurance of Jake to be counted.

---

OK, but in the above 2 lines the words "Jake" and "is" occurs on both lines so would that be considered a pair? Or the words "is" and "with" or "Jake" and "with". You must have some rules for what should be considered a pair and which words that shouldn't The word "going" also appears on both lines so maybe "is" and "going" is a pair. Or "going" and "Jake"...

Hello Joacim,

You do bring up a very good point.

I guess what you would have to do is add some code to disclude certain words from pairing up. Like "And" "Is" etc.

But with Penagate's code it only pairs up the ones that are specified by the user.
So I guess the for an auomatic pairing code you could exlude certain mainframe words like "And" or maybe something else the user might specify.
Stilekid007

Stile, I wrote another function that counts the number of words occuring in multiples of 2 in all sentences. Is that what you want or have I misunderstood?

Yes Penagate, That is what I want, will this count all the words or just Jake and ALexa (Or other specified search words), or will it count all pairs no matter what they are?

It counts all pairs in all sentences.

Here it is (keep the Copymemory dec'l and add reference to Microsoft Scripting Library):

VB Code:

'# Requires a reference to the Microsoft Scripting Runtime
Public Function CountCombos(ByVal lpFirstLine As Long, _
                            ByVal plngLinesUBound As Long) _
                           As Long
' IN: lpFirstLine:      Long pointer to the first element of an array
'                       containing the lines to search
' IN: plngLinesUBound:  Upper bound of the array containing the lines
' RETURNS: The number of two word combinations present in all the sentences.
 
    Dim Offset          As Long
    Dim strSentence     As String
    Dim astrWords()     As String
    Dim colWords        As Scripting.Dictionary
    Dim lngWordsPresent As Long
    Dim i               As Long
 
    Set colWords = New Scripting.Dictionary
 
    ' For each sentence
    For Offset = 0 To (plngLinesUBound * 4) Step 4
        strSentence = Space(255)
 
        CopyMemory ByVal VarPtr(strSentence), _
                   ByVal (lpFirstLine + Offset), _
                   4
 
        strSentence = Replace(Trim$(strSentence), "'s", vbNullString)
        
        ' Get all the words
        astrWords = Split(strSentence, " ")
        
        ' Add them to the dictionary
        For i = 0 To UBound(astrWords)
            If (colWords.Exists(astrWords(i))) Then
                colWords(astrWords(i)) = colWords(astrWords(i)) + 1
              Else
                colWords.Add astrWords(i), 1
            End If
        Next i
    Next Offset
    
    ' Return number of combos
    Dim varKeys         As Variant
 
    varKeys = colWords.Keys
 
    For i = 0 To UBound(varKeys)
        Debug.Print varKeys(i) & ": " & colWords(varKeys(i))
        If (colWords(varKeys(i)) > 1) Then _
            CountCombos = CountCombos + colWords(varKeys(i)) \ 2
    Next i
 
    Set colWords = Nothing
End Function
 
Public Sub Tester()
    Dim astrSentences(3) As String
    astrSentences(0) = "Jake and Alexa sat on a bench."
    astrSentences(1) = "Jake was very bored."
    astrSentences(2) = "Alexa was wearing Jake's thermal underwear."
    astrSentences(3) = "Useless sentence without the words J*** and A****."
 
    MsgBox CountCombos(VarPtr(astrSentences(0)), UBound(astrSentences))
End Sub

:)

Oh yeah, I forgot to mention, the sentences can only be a maximum of 255 characters long. If you want longer ones you will have to change the line where it says

VB Code:

strSentence = Space(255)

and put in an appropriate number.

Hello Penagate!

Ok, That is really sweet code, but I just realized something. The output is how many pairs of words are in the text. Not how many Combo's of like Jake and Alexa together. I thought this function was going to give me all the different combo's of words like bench and Jake or Alexa and bored. But I guess it gives me how many pairs of words like - how many Jakes appear in the text.

I guess I could still use this. And then to figure out how many times (EXAMPLE) Jake and Alexa appear as a combo, I would use your other function. Is this correct?

Thank you so much for that new function also! :thumb: :thumb: :thumb:
Stilekid077

Quote:

---

Originally Posted by stilekid007

I thought this function was going to give me all the different combo's of words like bench and Jake or Alexa and bored.

---

Well how do you know what is a combo? And yes my 2nd function counts the number of pairs of Jakes and benches etc.

Well I was saying Jake and Bench being a combo, instead of two jakes being a combo or two benches being a combo.

Am I misunderstanding?

Stilekid007

does the user input each combo at startup? are they predefined?

Well right now it is predifined but I could set it up for the user to input combo's at startup.

Stilekid007