convert address to string value?

Hi

Please help. Moving from vb to C++ and can't figure how to get the string value of the address for something like this:

Code:

---

#include <stdio.h>

int main ()
{
        // Make 52 cards in deck
        //define suit and card value for each
        int suit;char* cardNom;

        for (int i=1;i<=52;i++)
        {
          suit = i / 13;
          switch (suit)
          { case 0: cardNom = "Spades";
                    break;
            case 1: cardNom = "Hearts";
                    break;
            case 2: cardNom = "Clubs";
                    break;
            case 3: cardNom = "Diamonds";
                    break;
          }

        switch (i)
              { case 0:  cardNom = "Ace of " + char(cardNom);
                    break;
            case 10: cardNom = "Jack of " + char(cardNom);
                                break;
            case 11: cardNom = "Queen of " + char(cardNom);
                                break;
            case 12: cardNom = "King of " + char(cardNom);
                                break;
            default: cardNom = char(i + 1) + " " + char(cardNom);
                break;
          }
          printf ("\nCard number: %d" , i);
          printf (" is the %d" ,char(cardNom));
        }

  return 0;
}

---

Learn about proper string handling in C, or perhaps in C++. (C++ is easier, but C is closer to what you're already trying to do.) malloc, free, strcpy, strcat and strlen in C. std::string in C++.

You're handleing the cases like c++ strings although you're a little off. Make cardNom a string and use it like so:
case 0: cardNom += "Ace of " + cardNom; break;