[SOLVED]Make VB act as button...

Hi, is it possible so that when my VB form opens it mouseup and mousedown are automatically done without the user using the mouse? I need the click to be in the top left of the form if it's possible...

Thanks

Are you clicking on a certain control? You can call a click event thru code, or use an API to click anywhere on the screen.

What are you trying to do in your app? Invoke the system menu in the control box?
You can drop down the system menu using some APIs if that what your trying to do.

Im trying to click an image in the top left of the screen. I don't know what would be a good phrase or keywords to search for some code though.

Cheers

Is this in your app or another program?

You can use the SetCursorPos API to move the mouse to the screen coordinates you desire.

SetCursorPos

How would i find the required position of the top left of the form on load..?

Your form? Form1.Left & Form1.Top ???
If you need another programs positioning then you need to use FindWindow API.

What i mean is this:

SetCursorPos (frmMain.Top), (frmMain.Left)

How do i find the X,Y position of frmMain.Left and frmMain.Top on form_load?

Thanks so far :) Im getting there

That will give you the .top and .left coordinates. Try it!

Well SetCursorPos requires the X and Y coordinates to be in pixels and the Top and Left properties of a Form will always return them in Twips so you need to divide them with Screen.TwipsPerPixelX and Screen.TwipsPerPixelX.

But if this is your programs form why not just call the Image1_Click event procedure (if Image1 is the name of your image)?

Whatever i do the cursor starts at the top left of the monitor not the form..?

If your image is called Image1, just use this:

VB Code:

Option Explicit
 
Private Sub Form_Load()
 Image1_Click
End Sub
 
Private Sub Image1_Click()
  Beep
End Sub

and your image will be clicked.

if your app = true then
use Image1_Click(),
else
use the api
endif

I'm not trying to do image_click... I want VB to click on the image for me, so that MouseDown and MouseUp are used...The clicking isn't the problem, just starting the mouse in the top left hand side of the form.

Thanks

Mouse Down and Mouse up is the same thing as a click, and that's what will execute if you execute mouse down and mouse up. You can click on the form, if that's what you want using the Form_Click event.

What exactly are you trying to do? Perhaps I am misubderstanding...

I'm trying to take a screenie of an object. If i click the image whilst the programme is running it works, if i use image1_click it doesn't.

VB Code:

Public Sub Picture1_MouseDown(Button As Integer, Shift As Integer, X As Single, Y As Single)
Me.MousePointer = 99
Me.MouseIcon = Picture1.Picture
Picture1.Visible = False
End Sub
 
Public Sub Picture1_MouseUp(Button As Integer, Shift As Integer, X As Single, Y As Single)
Dim mousexy As PointAPI
GetCursorPos mousexy
SelWnd = WindowFromPoint(mousexy.X, mousexy.Y)
Me.MousePointer = 0
Picture1.Visible = True
End Sub
Private Sub form_load()
Picture1_Click
End Sub

You could use SPY++ to get a handle to the object that you want to click.
Is it your own app? Is it always the same app? Same object?

It's my own form, my own app. The picture box is always there, same place..

try this, just adjust to get exactly where you want

SetCursorPos Me.Left / Screen.TwipsPerPixelX + 10, Me.top / Screen.TwipsPerPixelY + 100

pete

If it is a Picture Box and not an Image control then use this code:

VB Code:

Private Declare Function SetCursorPos Lib "user32.dll" ( _
 ByVal x As Long, _
 ByVal y As Long) As Long
 
Private Declare Function GetWindowRect Lib "user32.dll" ( _
 ByVal hwnd As Long, _
 ByRef lpRect As RECT) As Long
 
Private Type RECT
    Left As Long
    Top As Long
    Right As Long
    Bottom As Long
End Type
 
Private Sub Form_Load()
    Dim r As RECT
    'Show the Form so the picture box is visible
    Me.Show
    Call GetWindowRect(Picture1.hWnd, r)
    Call SetCursorPos(r.Left, r.Top)
End Sub

Sorted! Thanks everyone :D :thumb: