too fast !!!!

In my program i'm doing 3 for ... next and in each of them i'm using filecopy source,destination to copy a bunch of file and i want to put the file that is currently being copy on a label(now copying c:\test.txt....)but i think that the for...next it's too fast and my label only get the last file that i copy.What could i do???

Add LabelName.Refresh after you change the Caption property.

Hi,
After each file copy you could put:

Code:

---

for ...
'copy file code
Label1.Refresh 'Add this
DoEvents 'Add this too if you want
next...

---

But if they are only really small files this may still not work as it will be going to fast!

Hope this helps

Shaun

If you really need to show all files you could either show all the files in the label: file1,file2,file3 or use a listbox to add all the files.

Heres a way to slow that down
after each label.refresh add

Code:

---

for ctr = 1 to 1000000
  aa = xx
next ctr

---

that should slow it down a bit, strange way of doing it but it worked for me when my progressbar moved so fast there was no point.