Split method => what to do with more than one space

Hi,

I'm able of splitting a string lik "Hallo, my name is.." with the "split method"
But what to do if there are more than one space between the words????

split(string, " ") only works if there's exactly one space between them... I've been searching for a couple of houres now

Anyone who can help?

What about doing a replace on the string first?

VB Code:

Dim splitStrings() As String
        Dim myString As String = "Hello  World! My  name is Lil  Ms Squirrel"
        myString = myString.Replace("  ", " ") 'replace any double spaces with a single space
        splitStrings = myString.Split(" ")

[QUOTE=Wirloff]Hi,

split(string, " ") only works if there's exactly one space between them...
QUOTE]

Hi,

What do you mean ? It still works and puts the second space of a pair on it's own into one of the array elements

Quote:

---

Originally Posted by Lil Ms Squirrel

What about doing a replace on the string first?

VB Code:

Dim splitStrings() As String
        Dim myString As String = "Hello  World! My  name is Lil  Ms Squirrel"
        myString = myString.Replace("  ", " ") 'replace any double spaces with a single space
        splitStrings = myString.Split(" ")

---

then squish that into 1 line of code :bigyello:

VB Code:

Dim splitStrings() As String = "Hello  World! My  name is Lil  Ms Squirrel".Replace("  ", " ").Split(" "c)

That's ok but it gets a bit messy when you get text with loads of spaces and not just 2.

If you had a string containing 10 consecutive spaces then you'd have to call replace 9 times!! Not very efficient!

Ignore multiple spaces completely, no replace required...

(look at the string this time!)

VB Code:

Dim splitStrings(), temp() As String
        Dim myString As String = [B]"Hello    World!     My   name                is Lil         Ms Squirrel"[/B]
        temp = myString.Split(" "c)
 
        Dim i, j, upper As Integer
        upper = temp.Length - 1
        splitStrings = New String(upper) {}       'create another string array with same no. of elements
 
        'copy all the actual words to the new array (don't copy any empty strings)
        j = -1
        For i = 0 To upper
            If temp(i).Length > 0 Then        'not empty?
                j += 1
                splitStrings(j) = temp(i)
            End If
        Next i
 
        temp = Nothing     'scrap the teporary array that has loads of empty strings in it
 
        If j >= 0 Then
            ReDim Preserve splitStrings(j)        'shrink the clean data array to fit the number of actual words found
        End If
 
        [B]'do something with splitstrings here[/B]

woss you could just do this though

VB Code:

Dim myString As String = "Hello    World!     My   name                is Lil         Ms Squirrel"
            Do Until myString.IndexOf("  ") = -1
                myString = myString.Replace("  ", " ")
            Loop

because im bored i did a speed test on them and they are neck and neck, but this code even finished slightly faster on a few high loop runs...