Simple news script

PHP Code:

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$host="localhost";
$user="me";
$password="you";
$database="hello";


      $connection = mysql_connect($host,$user,$password)or die ("Error Conecting To DB");
      $db = mysql_selectdb($database,$connection) or die ("bad table\db data");

      $query = "SELECT * FROM tblnews";
      $result = mysql_query($query);

      $nrows = mysql_num_rows($result);
      
      for ($i=0;$i<$nrows;$i++)
      {
        $row = mysql_fetch_array($result);
        echo $row;
      }
      

?> 


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and the error i am getting is

Quote:

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Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in path/index.php on line 15

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Any ideas on how to fix this?

also if i just wanted to select 3 coloums from the db how would i put my query


$query = "SELECT one two three FROM tblnews"; would that be right?

And i get the same error for this code

PHP Code:

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        $connection = mysql_connect($dbhost, $dbusername, $dbpassword);
    
       $query = "SELECT MAX(id) FROM tblnews";
       $result = mysql_db_query($database, $query);
     $count = mysql_fetch_array($result,MYSQL_ASSOC);
     
     echo $count 


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Arghhhhhhh

It was because it should be tblNews and not tblnews thats took me all day that has lol :-/

Remember:

PHP Code:

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or die(mysql_error()) 


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Is your friend. Putting that after mysql_ functions will help get you more specific errors. Such as, putting it after mysql_query() would've told you straight up that the table didn't exist.

Just a heads up.