Find the maximum value:
f(t) = -16t^2 + 48t + 300
Solve the exponential equation for t:
5 = 10e^-.00002845t
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Find the maximum value:
f(t) = -16t^2 + 48t + 300
Solve the exponential equation for t:
5 = 10e^-.00002845t
First derivate the first thingy:
f ' (t) = -32t + 48
Then set that one = zero
-32t + 48 = 0
32t = 48
t = 48/32
t = 3/2
thats where t is max/min
Now put t into the first thingy and see what you get.
f(3/2) = -16*(3/2)^2 + 48*(3/2) + 300
No idea what that is....and you are not getting me to find some peace of paper to calculate it either..:D
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I just interpolated with my calculator...
Max is where x=1.5, y=336
5 = 10e^-.00002845t
divide both sides by 10
1/2 = e^-.00002845t
take natural logs
ln(1/2) = -.00002845t
or (since -ln(2) = ln(1/2)):
t = ln(2)/.00002845
Thanks for the help, she want me to check her work!
:rolleyes:
She knows I not had math in 18 years.
:eek2: