Dividing by zero!!

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Originally Posted by Dave Sell

1) Dividing ANY number by zero is, and always will be, undefined.
2) Dividing ANY object by infinitely many small pieces will never amount to more than the original object

There will always just be the 1 pizza.

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Where is the proof? I have always been taught in methmatics that dividing by zero is infinity. Even if you draw the graph of 1/x, you can see it shoot off to infinity and back again as it passes zero. Isn't that proof enough?

What you're saying is incorrect. We take it to be infinity but it really is not. It is the limit of the function as x approaches zero. Since there is an infinity of values before x actually is equal to 0 the function can never actually equal infinity.

Limits are an interesting part of mathematics that presribe end values to functions that are undefined at these areas.

f(x) = 1/x
Domain of f(x) = Any number, real or otherwise.

f(3) = 0.333...
f(2) = 0.5
f(1) = 1
f(0.5) = 2
f(0.1) = 10
f(0) = Infinity

ByDef: Inf. is an unspecific or undefined value which cannot be measured because it By-Def's itself to be both a negative and postive value, for which the mid-point of itself is always... 0. Zero is part of the infinitive range because it is the most absolute value for the absolute infinitive small number which is closest to the midpoint of the absolute larger number which is too... infinity.

0.000000000000000000000000000000000000000000000000000000001
-Will get close to absolute zero, it may or may not reach it but it is an infinitive small number, and the absolute infinitive small number will always be 0. And the median between small-infinity will always be +/- 0.5, and it's inverse will always be +/- 1.

It can be the infinitive outside or inside the box, it's still infinity.

i = sqr(-1) = Inf
i^2 = sqr(-1) * sqr(-1)
i^2 = -1
i^4 = sqr(-1) * sqr(-1) * sqr(-1) * sqr(-1)
i^4 = -1 * -1
i^4 = 1
sqr(i^4) = (+/-) * -1
sqr(+/- -1)
=sqr(+-1)==i
=sqr(--1)==1
i = Inf OR 1

By prossessing i^3 in a similar way will have...
i = Inf OR -1
And because Inf works both ways...
i = (Inf OR 1) OR (Inf OR -1)
which of course, cancels out eveything and leaves...
0

So really, 0 and Inf are hand-in-hand with each other, they just don't like to spend time with each other that often. Since long-distance phone calls OR having Inf clinching to the legs of 0 doesn't work out so well. :)

*** math noob ***

So what is x/0????

:confused:

x / 0 is either Inf or 0 as long as x <> 0
= INV (x / 0) = 0
=(x / 0) == (0(x) = 1) == Inf

0 / 0 is Inf, 1, or 0
= (x / x) == 1
= (0 / x) == 0
= (x / 0) == Inf

0 / x is always 0 as long as x <> 0.

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Originally Posted by visualAd

Continued from here:
Where is the proof? I have always been taught in methmatics that dividing by zero is infinity. Even if you draw the graph of 1/x, you can see it shoot off to infinity and back again as it passes zero. Isn't that proof enough?

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Check out what Dr. Math has to say about it.
http://mathforum.org/library/drmath/view/53336.html

0/0 = 1
Proof:

Using L'Hospital's Rule
limit as x==>0 (x/x) =
limit as x==>0 [(d/dx)*x]/[(d/dx)*x] =
limit as x ==>0 1/1 = 1
kevin