Set path to Tomcat servlet container?

According to the Tomat docs Catalina is the name of the servlet container which needs its path to be set in the autoexec.bat file.
When i try to start up the server i get a message saying the CATALINA_HOME env variable is not defined correctly.
Does this look right?

Code:

---

SET BLASTER=A220 I7 D1 T2
SET SNDSCAPE=C:\WINDOWS
SET JAVA_HOME=C:\jdk1.4.2
SET PATH=%JAVA_HOME%\bin;%PATH%
SET CATALINA_HOME=C:\Jakarta\jakarta-tomcat-5.0.12

@SET CLASSPATH=C:\;C:\Java LF Graphics Repositoryjlfgr-1_0.jar;
C:\j2sdk1.4.1_05\jre\lib\ext\mysql-commector-java-3.0.14-production-bin.jar;

---

All these are set via DOS. Everything is working fine so far. Does anyone know if these remain if the server is taken down then restarted?

Code:

---

C:\> set JAVA_HOME=C:\jdk1.4.2
C:\> set PATH=%JAVA_HOME%\bin;%PATH%
C:\Jakarta> set CATALINA_HOME=C:\Jakarta\jakarta-tomcat-5.0.28

---

They don't. Set them in Control Panel -> System -> Advanced -> Environment Variables.

Im stuck running Win98 for the time being until i can run OSx on this G5 ive been eyeing or mepis linux on another computer ive been looking at :)

Then put the set commands into autoexec.bat.

That's what i did in the first place. If i dont get it to work dosent matter. Ill just set it on the fly, get the server up and leave it up.