Length of Diag in Grid?

Is there an easy method for finding the length of a diagnol line in a grid. Say, if I have:

Code:

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x x x x x x x x x x
x x x x x x x x x x
x x x x x x x x x x
x x x x x x x x x x
x x x x x x x x x x
x x x x x x x x x x

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And I know that x is 6 and y is 4 (bottom x). How could I find the length of any diagnol line, no matter where it starts?

a^2 + b^2 = c^2

Or...

Length = sqr(xdif^2 + ydif^2)

Or are you talking about the number of X's in a diagonal line in your grid?

Max (XDiff; YDiff)

Onlyalid if lines are either horizontal, vertical or at a 45 degree to that.

Are your lines composed of X's or are they composed of the endpoints of the line?

They're composed of X's. It's for a crossword puzzle, so I was trying to figure out how many letters could be in that line of spots.

But...I figured out my teacher wants us to do this a different way, so I don't really need to know anymore. :(

So is this resolved then?

Quote:

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Originally posted by Darkwraith
So is this resolved then?

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Yes and no. I don't need the answer anymore, but I'm still curious about how it can be accomplished.

If it's for a crossword, you're counting the "x" or the letters.
So use the max(XDiff,YDiff), or more precise max(Xdiff+1;YDiff+1).