whats wrong with this 1 line of code?

Code:

---

If Asc(Char) > 47 And Asc(Char) < 58 Then
'bla bla ba
end if

---

an error keeps coming up to that line

What error are you getting?

Invalid procedure call or argument (run time error 5)

i am assuming that this is what you want...
in the keypress event put this...

Select Case KeyAscii
Case 8 'backspace key
Case 13 'return key
cmdQuery(1).SetFocus
' control to set focus on enter
Case 48 To 57 ' chr(48) - chr(57)
' only numbers

End Select

If only entering numbers what you want, then you can use the Like operator as well.

Code:

---

Private Sub Text1_KeyPress(KeyAscii As Integer)
    'Allow backspace, tab and spacebar to be pressed
    If KeyAscii = 8 Or KeyAscii = 9 Or KeyAscii = 32 Then Exit Sub
    If Not Chr(KeyAscii) Like "#" Then KeyAscii = 0
End Sub

---

wait a sec, cna you correct my first line of code? becuase I need to make it so that you can only enter numbers and backspaces into a texbox

Private Sub Text1_KeyPress(KeyAscii As Integer)

Select Case KeyAscii
Case 8 'backspace key
Case 13 'return key
'next control to get focus
control.setfocus
Case 48 To 57 ' chr(48) - chr(57)
' only numbers

Case Else ' nothing else
KeyAscii = 0

End Select

End Sub



[Edited by larryn on 09-11-2000 at 06:31 PM]

can you make it something like:

If Asc(Char) > 47 And Asc(Char) < 58 Then

? that includes Ascii and stuff

If you have not put some value into char, then you will get the error you have mentioned.

I suggest you check your logic because the only error I can see possible in your line at runtime is empty variable.

The suggestions mentioned in other replies are a better approach to handling invalid characters on a Text_Change event. Better still in my view is to use the "masked edit control".

Cheers
Paul Lewis
(Back from holiday and looking for something to do)

Code:

---

Private Sub Text1_KeyPress(KeyAscii As Integer)
    If KeyAscii = 9 Or KeyAscii = 8 Or KeyAscii = 32 Then Exit Sub
    If Not (KeyAscii > 47 And KeyAscii < 58) Then KeyAscii = 0
End Sub

---

Code:

---

Option Explicit
'allow for backspace and numbers only

Private Sub Text1_KeyPress(KeyAscii As Integer)

If KeyAscii = 8 Or _
    KeyAscii >= 48 And KeyAscii <= 57 Then
    KeyAscii = KeyAscii
Else
    KeyAscii = 13
End If

End Sub

---