displaying output from a sequence

i used this code to generate a int N. I do this using (even)n=n/2 and (odd) n=3n+1 until n becomes 1. i use a System.out.println(n); to show the results, but what if i only wanted to show that last 4 numbers in the sequence... any suggestions.. thanks in advance annie

Code:

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int n = 0;
System.out.println("Please enter a number less than 100,000");
KBI.pause();
n = KBI.getint();
while(n != 1)
{
System.out.print(n + " ");
if(n % 2 == 0)
n = n / 2;
else
n = 3 * n + 1;
}
System.out.println(n);

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this mate?

PHP Code:

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import java.io.*;
import java.util.*;
public class document8{
   public static void main(String[] args)throws IOException{
      BufferedReader stdin=new BufferedReader(
         new InputStreamReader(System.in));
      System.out.println("Please enter a number less that 100,000 ");
      int n=Integer.parseInt(stdin.readLine());
      int[] n2=new int[n];
      int i=0;
      while(n!=1){
         System.out.print(n+" ");
         if(n%2==0) n/=2;
         else n=3*n+1;
         n2[i++]=n;
      }
      System.out.println(n);

      //display last 4
      int j=0;
      while(--i>=0&&j++<4) System.out.println(n2[i]);
   }
} 


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if not, i'm very very sorry.

:) cheers! annie
this is what i ended up with....

Code:

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//arrayList code    int n = 0;   
System.out.println("Please enter a number less than 100,000");    KBI.pause();   
n = KBI.getint();   
ArrayList al = new ArrayList();   
while(n != 1)   
{     
System.out.print(n + " ");     
if(n % 2 == 0)       
n = n / 2;     
else       
n = 3 * n + 1;       
if (al.size < 4)
{       
al.add(new Integer(n));     
} else
{       
al.remove(3);       
al.add(new Integer(n));     
}     
}   
for (int i=0;i<4;i++)
{     
System.out.println(((Integer) al.get(i)).toString());   
}

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