TOP URGENT - XML Serialisation.HELP

(VB.Net) I have a populated class. I want to serialise this class into a stream and then load it into an XML document.

Due to other constraints I do not want to write the stream to a file on the hard drive. I need to store it in memory then load it into an XML dom document.

Any examples anyone ?

Hi

Maybe you can use this?

VB Code:

Private st As IO.MemoryStream 'The stream to hold the data
 
    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        'Serializes the class to a memorystream.
        Dim mc As New MyClassToSerialize()
        st = New IO.MemoryStream()
 
        mc.A = 1
        mc.B = 2
        mc.C = 3
 
        mc.Save(st)
 
    End Sub
 
    Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
        'De-serializes the class from the memorystream
        Dim mc As MyClassToSerialize
        mc = MyClassToSerialize.Load(st)
        MsgBox(mc.A)
        MsgBox(mc.B)
        MsgBox(mc.C)
    End Sub
 
    Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click
        'Loads the serialized class as XML text.
        Dim S As String
        S = MyClassToSerialize.LoadToXML(st)
        MsgBox(S)
    End Sub
 
'The class to serialize.
<Serializable()> Public Class MyClassToSerialize
    Public A As Integer
    Public B As Integer
    Public C As Integer
 
    Public Sub Save(ByVal st As IO.Stream)
        Dim xml As New Xml.Serialization.XmlSerializer(GetType(MyClassToSerialize))
        st.Position = 0
 
        xml.Serialize(st, Me)
    End Sub
 
    Public Shared Function Load(ByVal st As IO.Stream) As MyClassToSerialize
        Dim xml As New Xml.Serialization.XmlSerializer(GetType(MyClassToSerialize))
        Dim mcts As MyClassToSerialize
        st.Position = 0
 
        mcts = DirectCast(xml.Deserialize(st), MyClassToSerialize)
        Return mcts
    End Function
    Public Shared Function LoadToXML(ByVal st As IO.Stream) As String
        Dim xml As New Xml.XmlDocument()
        st.Position = 0
        xml.Load(st)
        Return xml.OuterXml
    End Function
End Class

Thanks very much for that. Spot on. Works a treat.

:bigyello: :thumb: