Array Bounds

This should be simple, but it's not working.
The code below should show (to my mind) the values in the first dimension of the array, i.e., 12, 12, 13,...20.
Instead it shows 12, 12, then stops. This must be something obvious, but I can't see what the problem is. Any ideas? Thanks.

VB Code:

Dim i, j, l As Integer
Static x As Integer
Dim arrQuNumbers(,) = {{"12", "12", "13", "14", "15", "15", "15", "16", "17", "18", "20"}, _
                     {"16.1", "16.2", "17", "18", "19.1", "19.2", "19.3", "20", "21", "22", "24"}}
 
      
For i = arrQuNumbers.GetLowerBound(0) To arrQuNumbers.GetUpperBound(0)
      l = arrQuNumbers(0, i)
      MessageBox.Show(l)
Next

Maybe change it to:

l = arrQuNumbers(i, 0)

Is it row column, or column row, I don't remember offhand...

EDIT: Looking at that closer, you have an 11 columned array with two records in it? Is that what you wanted? Ugh, it's too late on Friday to have to think....:sick:

No, arrQuNumbers(i, 0) shows 12, 16 and stops.
What this should be is a two dimensioned array in 2 x 11 size.

Well, change it to

For i = arrQuNumbers.GetLowerBound(1) To arrQuNumbers.GetUpperBound(1) and it works. Maybe it is 0 is number of columns and 1 is number of rows? I can't say I ever do much with multiple dimension arrays, so it's all just speculation, but I tried it and it works that way

Quote:

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Originally posted by SeanGrebey
Well, change it to

For i = arrQuNumbers.GetLowerBound(1) To arrQuNumbers.GetUpperBound(1) and it works. Maybe it is 0 is number of columns and 1 is number of rows? I can't say I ever do much with multiple dimension arrays, so it's all just speculation, but I tried it and it works that way

---

It is misleading to look upon two dimensional arrays as Rows & Columns as in a table. Values are only stored in the elements of the final dimension of a multi-dimension array. No matter how many dimensions you have, all dimensions are represented by numbers which together identify the unique location at which a value can be stored. Whereas in a table you can have data stored in any row of any column

Also, you must be working with Option Strict Off to code like you have, which is not recommended.

Sorry taxes, but that doesn't help. I could do it with two different arrays; that's how I did it with the Access VBA program I'm trying to replace.
I'd try to do more now, but too much of Reagan stuff is going on.

VB Code:

'First Of All Lets Format the Array so that it is easy to see the mistake
        Dim arrQuNumbers(,) = { _
                            {"12", "12", "13", "14", "15", "15", "15", "16", "17", "18", "20"}, _ ' Row 1 (index 0)
                            {"16.1", "16.2", "17", "18", "19.1", "19.2", "19.3", "20", "21", "22", "24"} _ ' Row 2 (index 1)
                             }
 
        'Now I am going to explain this a little deeper w/ code
 
        MsgBox("The First Array Bound (0) has a Upperbound of: " & arrQuNumbers.GetUpperBound(0))
        MsgBox("The Second Array Bound (1) has a Upperbound of: " & arrQuNumbers.GetUpperBound(1))
 
        'Here is a simple table of your values and how it corrisponds to the array bounds
 
        'Assume the first bound is the column index(x) and the second bound is the row index(y)
 
        'Table
        '  |   0     1     2   3   4     5       6   7   8   9  10
        '---------------------------------------------------------
        '0 |    12,   12, 13, 14,   15,   15,   15, 16, 17, 18, 20
        '1 |  16.1, 16.2, 17, 18, 19.1, 19.2, 19.3, 20, 21, 22, 24
 
        'So Now that you understand that (1,1) Refers to  value 16.2 Then
 
        MsgBox("This Value: arrQuNumbers(1, 1) is also " & arrQuNumbers(1, 1))
 
        'So to do what you orginally wanted to do ....
 
        For I As Integer = 0 To arrQuNumbers.GetUpperBound(1)
            MsgBox(arrQuNumbers(0, I))
        Next
 
        'Now to display both rows....
 
        For x As Integer = 0 To arrQuNumbers.GetUpperBound(0)
            For j As Integer = 0 To arrQuNumbers.GetUpperBound(1)
                MsgBox(arrQuNumbers(x, j))
            Next
        Next

Edit: Missed a 15 in first row ;(

How come you don't have Option Explicit on?

Here, try this code:

VB Code:

Dim i, j As Integer
        Dim l As Double
 
        Static x As Integer
        Dim arrQuNumbers(,) As Decimal = {{12, 12, 13, 14, 15, 15, 15, 16, 17, 18, 20}, _
                             {CDec("16.1"), CDec("16.2"), 17, 18, CDec("19.1"), CDec("19.2"), CDec("19.3"), 20, 21, 22, 24}}
 
        For i = 0 To UBound(arrQuNumbers, 2)
            l = arrQuNumbers(0, i)
            MessageBox.Show(l.ToString)
 
        Next

The only difficulty I faced was placing the decimal values into the array. I think I have done it correctly.

I wasn't aware of ABX's post, dangnabbit.

Oh, and leave the dead white guy alone. Write your programs. :)

yeah.... i was surpirised that someone else didnt catch the mistake....

Those kind of mistakes cost me hours and hours of screwing around ;(

Hey, at least it isn't a case sensitive language.

:)

Quote:

---

Originally posted by salvelinus
Sorry taxes, but that doesn't help. I could do it with two different arrays; that's how I did it with the Access VBA program I'm trying to replace.
I'd try to do more now, but too much of Reagan stuff is going on.

---

I obviously have not made myself clear.

In your first post you said

"The code below should show (to my mind) the values in the first dimension of the array, i.e., 12, 12, 13"

That is the point to which I was referring. All values were stored in the Second Dimension. Your second post clearly indicates you knew the array was of 2 dimensions with 2 elements in the first dimension and 11 elements in the second dimension.

Thanks, guys, I'll try those out at work Monday.
The Option question isn't up to me, but I'll bring it up to those whom it is.
I've tried different ways. I'll try these. May be getting confused between the different vb versions I work with. Rarely use multidimension arrays. What this should eventually do is loop through some text, adding the value in the second dimension to the text after the occurence of the first dimension in the text (not replace it).
I did this in Access VBA with two separate arrays, and could do the same here. But I'm trying to write optimized code. Sometimes bugs the boss, who wants it Now, but I want it the best I can do.
I'm not sure where the mistake that <abx> says occurs. I know that arrQuNumbers(1, 1) refers to 16.2. So arrQuNumbers(0, i) should loop through the elements in the first dimension. But that didn't work either.
Needless to say, this is just test code to see how it works.

Quote:

---

Originally posted by taxes
I obviously have not made myself clear.

In your first post you said

"The code below should show (to my mind) the values in the first dimension of the array, i.e., 12, 12, 13"

That is the point to which I was referring. All values were stored in the Second Dimension. Your second post clearly indicates you knew the array was of 2 dimensions with 2 elements in the first dimension and 11 elements in the second dimension.

---

Uh, no, I thought there were 11 elements in both dimensions. I thought the array was 2 rows, 11 columns each. Used an example from a book. Where was my mistake in the first dimension? Thanks, I really appreciate the help. This has got to be a brain fart issue.

your mistake was:

VB Code:

For i = arrQuNumbers.GetLowerBound(0) To [b]arrQuNumbers.GetUpperBound(0)[/b]
      l = arrQuNumbers(0, i)
      MessageBox.Show(l)
Next

This should be GetUpperbound(1) because

GetUpperbound(0) will return the value 1 because it is refering to the row index

thats why you get 12,12 because the first two numbers are both 12's

arrQuNumbers(0,0) = 12
arrQuNumbers(0,1) = 12
the second index is the value that refers to the column
now the other value refers to the row index so you are saying that you want to access values (0,0), (0,1)

btw: GetLowerBound isn't required any more because arrays must have a base of 0

Quote:

---

Originally posted by salvelinus
What this should eventually do is loop through some text, adding the value in the second dimension to the text after the occurence of the first dimension in the text (not replace it).
I did this in Access VBA with two separate arrays, and could do the same here. But I'm trying to write optimized code. Sometimes bugs the boss, who wants it Now, but I want it the best I can do.
I'm not sure where the mistake that <abx> says occurs. I know that arrQuNumbers(1, 1) refers to 16.2. So arrQuNumbers(0, i) should loop through the elements in the first dimension. But that didn't work either.
Needless to say, this is just test code to see how it works.

---

Referring to the above and ABX's last post, you can ONLY use the reference to Rows & Columns in Two dimensional arrays. But, even then, THEY DO NOT FUNCTION LIKE ROWS & COLUMNS. There are no values at all stored in the Row number. The values are stored only in the elements held in the last dimension. The values of the first dimension are solely the Row numbers, normally starting at 0 ( but in VB.NET you can create dimensions based on other numbers - with great difficulty and it is not CLS compliant so you will have difficulty if you ever want to share them with other .Net languages and don't even think about it for a single dimension array (also called Vectors)).

If you want to store two separate values relating to a common unifier then you will HAVE to use two separate 2 dimension arrays, using the first (and second if necessary) dimension numbers to link those values. In it's simplest form arrTest1(3,0) carries values which you want to which you want to relate in arrTest2(3,0). Most people never have any need to go beyond a two dimensional array. I suppose you could design a two dimension array where the first dimension denotes the class of data involved and then expand the second dimension to a point where if could hold sufficient data to achieve your objective, but there is insufficient information on your objective to determine this.

With regard to ABX's last post, in GetUpperBound(0) the 0 gets the upperbound of the FIRST dimension and that is NOT where the values are stored. GetUpperBound(1) gets the upperbound of the SECOND dimension, where the values ARE stored. You do, of course, need to know the upperbounds of all the dimensions(in your case both dimensions) in order to extract all the values
Boy, I'm glad you are not working in 5 dimension arrays:bigyello: