insert into db - resolved

Hi Guys.
im trying to insert a line into mysql with the follong code

PHP Code:

---

mysql_connect("localhost","root","InsertYourPasswordHere");
mysql_select_db ("mywakeupcall");
$query = "INSERT INTO database(fname,lname,alarm,phone) VALUES('".$_POST['firstname']."','".$_POST['lastname']."','".$_POST['atime']."','".$_POST['telephone']."')"; 

if (! mysql_query($query))
    die ('Query Failed: ' . mysql_error());

echo 'Item Entered.'; 


---

however the error msg that comes back is

Query Failed: You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near 'database(fname,lname,alarm,phone) VALUES('samantha','murray','1

andI cant find out whatthe problem is. fname and lname is text and the alarm and phone is numbers.

any help would be great thanks

chrisio

You have a table named "database"? I suggest changing it to something else. Database is most likely a reserved keyword, and shouldn't be used in tables/fields names.

ok. table name changed and nodifference :( i get the same error message as before.

PHP Code:

---


<?php
$temp1 = $_POST['firstname'];
$temp2 = $_POST['lastname'];
$temp3 = $_POST['atime'];
$temp4 = $_POST['telephone'];

mysql_connect("localhost","root","InsertYourPasswordHere");
mysql_select_db ("mywakeupcall");

$query = "INSERT INTO tblmain ('fname', 'lname', 'alarm', 'phone' VALUES ($temp1, $temp2, $temp3, $temp4)";

if (! mysql_query($query))
    die ('Query Failed: ' . mysql_error());

echo 'Item Entered.';

?>

---

error message :

Query Failed: You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near ''fname', 'lname', 'alarm', 'phone' VALUES (samantha, murray, 10


im very puzzled.

if i also just use

INSERT INTO tblmain VALUES ($temp1, $temp2, $temp3, $temp4)";

it throws back this error message

Query Failed: Unknown column 'samantha' in 'field list'

the field names in the db are as follows

fname (varchar20)
lname (varchar20)
alarm (int4)
phone (int11)

thanks again

You can't just throw variables into a string without putting them in quotes. And when you are inserting, you have to enclose values in single quotes. Hence: singlequote|doublequote|dot|variablename|dot|doublequote|singlequote

PHP Code:

---

<?php
mysql_connect("localhost","root","InsertYourPasswordHere");
mysql_select_db ("mywakeupcall");

$query = "INSERT INTO tblmain ('fname', 'lname', 'alarm', 'phone') VALUES ('" . $_POST['firstname'] . "', '" . $_POST['lastname'] . "', '" . $_POST['atime'] . "', '" . $_POST['telephone'] . "')";

$pass = @mysql_query($query) or die('Query Failed: ' . mysql_error());

if ($pass)
echo 'Item Entered.';
?>

---

Quote:

---

Originally posted by ober0330
You can't just throw variables into a string without putting them in quotes. And when you are inserting, you have to enclose values in single quotes. Hence: singlequote|doublequote|dot|variablename|dot|doublequote|singlequote

PHP Code:

---

<?php
mysql_connect("localhost","root","InsertYourPasswordHere");
mysql_select_db ("mywakeupcall");

$query = "INSERT INTO tblmain ('fname', 'lname', 'alarm', 'phone') VALUES ('" . $_POST['firstname'] . "', '" . $_POST['lastname'] . "', '" . $_POST['atime'] . "', '" . $_POST['telephone'] . "')";

$pass = @mysql_query($query) or die('Query Failed: ' . mysql_error());

if ($pass)
echo 'Item Entered.';
?>

---

---

hi.
I have tried that and get the exate same error msg so imcompleaty stuck now.

help?

Try this:

PHP Code:

---

<?php
mysql_connect("localhost","root","InsertYourPasswordHere");
mysql_select_db ("mywakeupcall");

$query = "INSERT INTO tblmain (fname, lname, alarm, phone) VALUES ('" . $_POST['firstname'] . "', '" . $_POST['lastname'] . "', '" . $_POST['atime'] . "', '" . $_POST['telephone'] . "')";

$pass = @mysql_query($query) or die('Query Failed: ' . mysql_error());

if ($pass)
echo 'Item Entered.';
?>

---

PERFECT THANKS VERY MUCH:D :D

You're welcome. :wave: