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3 chains of light globes
the chains are in parallel
they're connected to a battery
the lightglobes in the chains are in series
one of the lightglobes in the 2nd chain breaks
What happens to the brightness of the other two chains?
a) They get brighter
b) They stay the same
I've done it two different ways, and have two seemingly correct ideas working.
What's the answer! :p
(And reasoning too)
they stay the same
Chains dont glow the lights do :confused:
you knew what i meant,
how come :o?
If we are talking of the lightglobes then they turn off because the circuit is broken :)
It would look like this, with the lit globes 50% brighter than before the breakage.
http://www.vbforums.com/attachment.p...postid=1709056
They stay the same because the current across all the chains has the same voltage whether it was only 2 or 20. That's what i was taught.
What the **** is a light globe anyway?
Does it still conduct when it's broken?
light globe = globe etc
that's what i thought wossname
i don't think the circuit is really broken, only one bit of it is,
the 3 chains are connected to the same point in the circuit
:o
Light globe = light bulb?
Wouldn't the remaining lightbulbs get brighter. If you had thousands connected to 1 battery they'd be dim wouldn't they?
Looking at the diagram the left and right bulbs would stay the same but all the center ones would go out.
I think so anyway. Putting them in series will dim them but putting them in parrallel splits the amps. AKA the amount of bulbs it could support :D
Easy answer: The lamps stay the same brightness - Loads connected in parallel have no impact on each other. If you don't believe me just try switching all the lights in your house on and then turning one off - do the others get brighter? No because they are connected in parallel.
Complex answer: It depends on the capacity (VA rating) of the power source. If the three bulbs are drawing more power than the source can supply then they will be glowing dimmer than they should. Removing one will decrease the load on the source and could result in the remaining lamps having full power. ie. 3x60W bulbs running from a 150VA source will only be burning at the equivilent of a 50W bulb (150/3). Remove one and the load is now 120W which the source can supply thus the bulbs burn at 60W - that is they are brighter.
(Ex lighting engineer, and Electronic Systems Engineer graduate:))
You'd think that, but physics proves otherwise, something because the electrons don't loose energy by going down multiple paths, but by going down a series. Hence why when you have a short curcuit, none come on and the battery usually gets very hot and may explode.Quote:
Originally posted by SLH
Wouldn't the remaining lightbulbs get brighter. If you had thousands connected to 1 battery they'd be dim wouldn't they?
Electricity follows the path of least resistance :)
resistance is futile
Ah, that's why i was never good at physics. :DQuote:
Originally posted by Ideas Man
You'd think that, but physics proves otherwise, something because the electrons don't loose energy by going down multiple paths, but by going down a series. Hence why when you have a short curcuit, none come on and the battery usually gets very hot and may explode.
With an avatar like yours i guess you should know this one.....
Technically, and no one has ever accused me of being too technical,Quote:
Originally posted by BodwadUK
Electricity follows the path of least resistance :)
electricity follows ALL paths. It's just that the path of least resistance
gets the most traffic, hence the abundance of trash bins.
Short curcuits occur due to a path with less resistance. I didnt think the circuit had any power in event of a short circuit :confused:
Very well spotted :bigyello:Quote:
Originally posted by SLH
With an avatar like yours i guess you should know this one.....
Practically speaking, yes.Quote:
Originally posted by BodwadUK
Short curcuits occur due to a path with less resistance. I didnt think the circuit had any power in event of a short circuit :confused:
Ohms law is I = V/r
as your resistance(r) approaches 0, as in a short circuit,
the electricity amps (I) will approach infinity.
BUT
there will still be a teeny weeny bit of electricity going through
the rest of the circuit.
It's the same principle that makes a pound of bricks heavier
than a pound of feathers.
:confused: